Question

If f is the function defined by f (x) = (1/x-1)/(x-1), then lim f (x) is equivalent to what?

Answer 1

The limit of the function as x tends to 2 is 1

Given the function f(X) expressed as;

$f(x)=\frac{\frac{1}{x-1}}{x-1}$

This can also be expressed as:

$f(x) = \frac{1}{(x-1)^2}$

Assuming the limit of f(x) approaches 2, this means we are to substitute x = 2 into the function as shown

$\lim_{x \to2} \frac{1}{(x-1)^2}\\= \frac{1}{(2-1)^2}\\=\frac{1}{1^2}\\=1$

This shows that the limit of the function as x tends to 2 is 1

Learn more here: brainly.com/question/23935467