First take note of the domain of <em>f(x)</em> ; the square root term is defined as long as <em>x</em> - <em>x</em> ² ≥ 0, or 0 ≤ <em>x</em> ≤ 1.
Check the value of <em>f(x)</em> at these endpoints:
<em>f</em> (0) = 0
<em>f</em> (1) = 0
Take the derivative of <em>f(x)</em> :
For <em>x</em> ≠ 0, we can eliminate the √<em>x</em> term in the denominator:
<em>f(x)</em> has critical points where <em>f '(x)</em> is zero or undefined. We know about the undefined case, which occurs at the boundary of the domain of <em>f(x)</em>. Check where <em>f '(x)</em> = 0 :
√<em>x</em> (3 - 4<em>x</em>) = 0
√<em>x</em> = 0 <u>or</u> 3 - 4<em>x</em> = 0
The first case gives <em>x</em> = 0, which we ignore. The second leaves us with <em>x</em> = 3/4, at which point we get a maximum of max{<em>f(x) </em>} = 3√3 / 2.
The numbers you are looking for are -11 and -1.
Answer:
See below.
Step-by-step explanation:
It can really help to think when you see |expression| that it means the distance from expression to zero.
(a) |x| < 7 means the distance from x to 0 is less than 7. That puts x between -7 and 7. The solution set is -7 < x < 7.
(b) |x + 3| < 9 means that the distance from x + 3 to 0 is less than 9. That puts x + 3 between -9 and 9:
-9 < x + 3 < 9 Now subtract 3 from all three parts.
-12 < x < 6
(c) |y - 8| > 11 means that the distance from y - 8 to 0 is more than 11 units. That puts y - 8 in one of two places: left of -11 or right of 11.
(g) 
means that the distance from 3x - 1 to 0 is more than (or equal to) 18. Another way to say it is, 3x - 1 is farther from 0 than 18 units. That puts 3x - 1 in one of two places: to the left of -18 or to the right of 18.
means that 4y + 3 is closer to 0 than 13; it is between -13 and 13.
(That last fraction is 10/4 simplified.)
The range is [4, infinity], {y|y greater than or equal to 4}
Answer:
Step-by-step explanation:
