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Yuki888 [10]
3 years ago
7

Fun with Characters

Computers and Technology
1 answer:
Inessa [10]3 years ago
4 0

The program is an illustration of conditional statements.

Conditional statements are statements whose execution is dependent on the truth value of the condition.

The checkCharacter() method in Java, where comments are used to explain each line is as follows:

//This defines the checkCharacter() method

public static String checkCharacter(String inputString, int index){

  //This checks if the character at the index, is a digit

  if(Character.isDigit(inputString.charAt(index))){

      //If yes, it returns "Digit"  

      return "Character "+inputString.charAt(index)+" is a digit";

  }

  //This checks if the character at the index, is a letter

  else if(Character.isLetter(inputString.charAt(index))){

      //If yes, it returns "letter"

      return "Character "+inputString.charAt(index)+" is a Letter";

  }

  //This checks if the character at the index, is a white space

  else if(inputString.charAt(index) ==' '){

      //If yes, it returns "white space"

      return "Character "+inputString.charAt(index)+" is a white space";

  }

  #If all the above conditions are false

   else{

      //If yes, it returns "unknown character"

      return "Character "+inputString.charAt(index)+" is an unknown character";

  }

}

The string to return depends on the character at the index.

Read more about similar programs at:

brainly.com/question/25127567

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In python please:
Vikki [24]

Answer:

"

if 'marsupial' in dictionary:

   del dictionary['marsupial']

else:

   print("The key marsupial is not in the dictionary")

"

Explanation:

So you can use the keyword "in" to check if a certain key exists.

So the following code:

"

if key in object:

   # some code

"

will only run if the value of "key" is a key in the object dictionary.

So using this, we can check if the string "marsupial' exists in the dictionary.

"

if 'marsupial' in dictionary:

   # code

"

Since you never gave the variable name for the variable that references a dictionary, I'm just going to use the variable name "dictionary"

Anyways, to delete a key, there are two methods.

"

del dictionary[key]

dictionary.pop(key)

"

Both will raise the error "KeyError" if the key doesn't exist in the dictionary, although there is method with pop that causes an error to not be raised, but that isn[t necessary in this case, since you're using the if statement to check if it's in the dictionary first.

So I'll just use del dictionary[key] method here

"

if 'marsupial' in dictionary:

   del dictionary['marsupial']

else:

   print("The key marsupial is not in the dictionary")

"

The last part which I just added in the code is just an else statement which will only run if the key 'marsupial' is not in the dictionary.

3 0
2 years ago
A location in memory used for storing data and given a name in a computer program is called a because the data in the location c
Gekata [30.6K]
Variable

----------------------------------
6 0
4 years ago
What is up what everbody up to
andriy [413]

Answer: Eating chicken. drinking cool aid, and playing basketball

Explanation: look at my skin color and u will understand

5 0
3 years ago
Read 2 more answers
3. Of the following pieces of information in a document, for which would you most likely insert a mail merge field? A. First nam
yuradex [85]
I would suggest the answer would be both A and D, mail merge is used to specify different field for different recipients. 
4 0
3 years ago
Read 2 more answers
Examine the efficiency the various recovery algorithms used in deadlock handling
sineoko [7]

Solution:

The process of transaction can guarantee the reliability of business applications. Locking resources is widely used in distributed transaction management (e.g; two phase commit, 2PC) to keep the system consistent. The locking mechanism, however, potentially results in various deadlocks. In service oriented architecture, the deadlock problem becomes even worse because multiple transactions try to lock shared resources in the unexpectable way due to the more randomicity of transaction requests, which has not been solved by existing research results. In this paper, we investigate how to prevent local deadlocks, caused by the resource competition among multiple sub-transactions of a gl obal transaction, and global deadlocks from the competition among different global transactions. We propose a replication based approach to avoid the local deadlocks, and a timestamp based approach to significantly mitigate the global deadlocks. A general algorithm is designed for both local and global deadlock prevention. The experimental results demonstrate the effectiveness and efficiency of our deadlock prevention approach. Further, it is also proved that our approach provides higher system performance than traditional resource allocation schemes.

This is the required answer.

4 0
3 years ago
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