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Georgia [21]
3 years ago
7

Simplify. (−5)^5(−5)^−6

Mathematics
1 answer:
Musya8 [376]3 years ago
6 0

Answer:

Step-by-step explanation:

In exponents multiplication, if bases are same, add the powers

a^{m}*a^{n} =a^{m+n}\\\\\\(-5)^{5}*(-5)^{-6}=9-5)^{(-5) + (-6)} = (-5)^{-11}

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A circular fountain has a radius of 6.1 feet. Find its diameter and circumference to the nearest hundredth. Use 3.14 for π.
cupoosta [38]

Answer:

d= 12.2 C= 38.3

Step-by-step explanation:

The radius of a circle is half of the diameter so multiply 6.1 by 2

6.1 x 2 = 12.2 ft

To find the circumference:

C = 2πr

C = 2(3.14)(6.1)

C= 2(19.154)

C= 38.3

6 0
3 years ago
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6. In a jar of 650 marbles, 20% of the marbles are red.<br> How many marbles are not red
Degger [83]

Answer:

Step-by-step explanation:

20% of 650

1/5 of 650

130=red

520= not red

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I'm not really sure how to fro it, can anyone help me?
kondaur [170]
Since the ratio is 5:4, they had to multiply 5x11 to get the 55. Now multiply the 4x11 to get 44. When you add the 55 and 44 that's 99 which only leaves 1 for the independent.
5 0
3 years ago
An airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservation
Andrej [43]

Answer:

0.23328,2.4

Step-by-step explanation:

Given that an airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservations for a trip, and a passenger must have a reservation.

Assuming independence we can say persons who do not show up is binomial with p = 0.4 and n = 6

a) If six reservations are made, what is the probability that at least one individual with a reservation cannot be accommodated on the trip

= P(X\leq 1)\\=0.23328

b) Expected no of available places = E(x)=np = 6(0.4) = 2.4

8 0
3 years ago
In triangle JKL, tan(b°) = 3/4 and cos(b°) =4/5. If triangle JKL is dilated by a scale factor of 1/2, what is sin(b°)?
zysi [14]

Answer:

\sin (b^\circ)=\dfrac{3}{5}.

Step-by-step explanation:

It is given that,

\tan (b^\circ)=\dfrac{3}{4}

\cos (b^\circ)=\dfrac{4}{5}

If a figure is dilated, then the image is similar to the figure. It means the corresponding angles of figure and image are congruent.  

So, the value of sin(b°) after dilation is equal to the value of sin(b°) before dilation.

We know that,

\dfrac{\sin \theta}{\cos \theta}=\tan \theta

\dfrac{\sin (b^\circ)}{\cos (b^\circ)}=\tan (b^\circ)

\sin (b^\circ)=\tan (b^\circ)\times \cos (b^\circ)

\sin (b^\circ)=\dfrac{3}{4}\times \dfrac{4}{5}

\sin (b^\circ)=\dfrac{3}{5}

Therefore, \sin (b^\circ)=\dfrac{3}{5}.

5 0
4 years ago
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