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3 years ago

Use the expression 3t+4+4t+3 explain how you know which terms can be combined to find the sum\

Mathematics

1 answer:

olga2289 [7]3 years ago

7 0

Answer:

7t+7

Step-by-step explanation:

The 2 numbers with the t you need to add them, then add the other numbers without the t. Then you get your answer.

3t+4t=7t

3+4=7

7t+7 is your answer

I hope this helps you.

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4x2 +9y2 = 72

Kamila [148]

Answer:

<h2> $\bold{\left(\dfrac{3}{13}\ ,\ \dfrac{4\sqrt{13}}{13}\right)\qquad\vee\qquad \left(\dfrac{3}{13}\ ,\ -\dfrac{4\sqrt{13}}{13}\right)}$ </h2>

Step-by-step explanation:

x - y² = -1 ⇒ - y² = - x - 1 ⇒ y² = x + 1 {x≥-1}

4x² + 9y² = 72

4x² + 9(x + 1)² = 72

4x² + 9(x² + 2x + 1) = 72

4x² + 9x² + 18x + 9 - 72 = 0

13x² + 18x - 63 = 0 ⇒ a = 13, b = 18, c = -63

$x=\dfrac{-18\pm\sqrt{18^2-4\cdot13\cdot(-63)}}{2\cdot13}=\dfrac{-18\pm\sqrt{324+252}}{26}=\dfrac{-18\pm\sqrt{576}}{26}\\\\x=\dfrac{-18+24}{26}=\dfrac3{13}\qquad\vee\qquad x=\dfrac{-18-24}{26}=-\dfrac{21}{13}\\\\ y^2= x + 1\quad\iff\quad x\ge-1\\\\y^2=\dfrac3{13}+1\\\\ y^2=\dfrac{16}{13}\\\\y=\dfrac{4}{\sqrt{13}}=\dfrac{4\sqrt{13}}{13}\qquad\vee\qquad y=-\dfrac{4\sqrt{13}}{13}$

4 0

3 years ago

Keisha bakes a pan of brownies for family picnic. She takes 1/2 of the brownies to the picnic. At the picnic, her family eats 3/

Rzqust [24]

Answer:

Keisha has 1/8th of the brownie pan that she brings back.

Step-by-step explanation:

To start, take a whole pan and subtract the 1/2 she left at home and the 3/8 that her family ate.

1 - 1/2 - 3/8 = Leftover

We also need to give them common denominators to complete the action.

8/8 - 4/8 - 3/8 = Leftover

1/8 = Leftover

7 0

4 years ago

A bag contains 5 red marbles, 3 blue marbles and 6 green marbles. If two marbles are drawn out of the bag, what is the exact pro

Nikitich [7]

Answer:

the probability to select both marbles to be red is 36% round up to the nearest whole number.

Step-by-step explanation:

8 0

3 years ago

which figure would be rotated 360 degrees to create a cone with an altitude perpendicular to its base?

melamori03 [73]

Just look at the perpendicular cross section, which would be an isosceles triangle. Split that in half vertically and you get a right triangle.

8 0

3 years ago

Let , −5−6 be a point on the terminal side of θ . find the exact values of cosθ , cscθ , and tanθ .

gizmo_the_mogwai [7]

Given that point (-5, -6) is a point on the terminal side of θ. Since both the x coordinate and the y-coordinate are negative, θ is in the third quadrant.

The side opposite θ is -6 and the side adjacent θ is -5.

The hypothenus is given by $\sqrt{(-6)^+(-5)^2}=\sqrt{36+25}=\sqrt{61}$

The exact value of cosθ is given by:

$\cos\theta= \frac{adjacent}{hypothenuse} = \frac{-5}{\sqrt{61}}$

The exact value of cscθ is given by:

$\csc\theta= \frac{hypothenuse}{opposite} = \frac{\sqrt{61}}{-6}$ 

The exact value of tanθ is given by:

$\tan\theta= \frac{opposite}{adjacent} = \frac{-6}{-5} =1.2$

5 0

4 years ago