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4 years ago

Evaluate each permutation 7p3

1 answer:

3 0

If you have a graphing calculator, you could use it to solve this question.

If you have a TI-84, go to MATH then PROB then 3: nPr

From there, all you have to do is type in 7 and 3 in their correct spots to get 210 as your answer.

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Of the entering class at a college, 75% attended public high school, 15% attended private high school, and 10% were home s

poizon [28]

Answer:

a)- 0.7670

b)- 0.176

c)- 0.809

Step-by-step explanation:

Let us assume that,

P(A)= Attended Public School

=0.75

P(B)= Attended Private School

=0.15

P(C)= Attended Home School

=0.10

P(E)= Student made the Dean's list

Then,

P(E/A)= Probability of Student made the Dean's list given that he\she attended Public School = 0.18

P(E/B)= Probability of Student made the Dean's list given that he\she attended Private School = 0.16

P(E/C)= Probability of Student made the Dean's list given that he\she is from Home School = 0.17

a)- P(E)= Probability that Student made the Dean's List

= P(A) × P(E/A) + P(B) × P(E/B) + P(C) × P(E/C)

= 0.75 × 0.18 + 0.15 × 0.16 + 0.10 × 0.17

= 0.176

b)- P(A/E) = Probability that Student came from a Public high school, given that Student made the Dean's list

= [ P(E/A) × P(A) ] ÷ P(E)

= [ 0.18 × 0.75 ] ÷ 0.176

= 0.767

c)- P(C'/E') = Probability that Student was not home schooled, given that the Student did not make the Dean's list

= [ P(E'/C') × P(C') ] ÷ P(E')

= [ 0.741 × 0.90 ] ÷ 0.82 [∵P(E'/C')=P(A)×P(E'/A)+P(B)×P(E'/B)

= 0.75 × 0.82 + 0.15 × 0.84

= 0.741

= 0.809

8 0

4 years ago

Sino pilipino dito? mga bwesit taó dito tang inà

valkas [14]

Answer:

ako

Step-by-step explanation:

kalma lang, di naman kelangan magmura...

6 0

3 years ago

Damm [24]

Answer:

A. $1.25x + 7y \le 110$

Step-by-step explanation:

No more than 110 lb total will be grilled. That means that the amount of meat that will be grilled is equal to or less than 110 lb.

$total~weight \le 110$

The total weight is made up of the weight of the chicken legs plus the weight of the racks of ribs.

1 chicken leg weighs 1.25 lb.

x chicken legs weigh 1.25x.

1 rack of ribs weighs 7 lb.

y racks of ribs weight 7y.

The total weight of the meat is

1.25x + 7y.

That weigh must be less than or equal to 110 lb.

$1.25x + 7y \le 110$

Answer: A. $1.25x + 7y \le 110$

8 0

3 years ago

Read 2 more answers

3.) How many total drinks were sold in the three-hour time period?

svlad2 [7]

Answer:

Hello

Step-by-step explanation:

what are the prices? I guess hours are on the x axis and prices on the y?

7 0

4 years ago

Help pls this is for my math test.

Stells [14]

Answer:

D is the answers for the question

Step-by-step explanation:

please mark me as brainlest

5 0

3 years ago

Read 2 more answers