Find the area of a circular pizza that has a diameter of 12 inches.
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Answer:
Given point (5,-12) falls into IV quadrant
<u>The right triangle with legs of 5 and -12, and hypotenuse is:</u>
- √5² + (-12)² = √25+144 = √169 = 13
<u>Value of sinθ, cosθ, and tanθ:</u>
- sin θ = -12/13
- cos θ = 5/13
- tan θ = -12/5
