Jane & Jim spent the same amount of money today. If Jim spent

Mathematics

1 answer:

Assoli18 [71]3 years ago

6 0

Answer:4$

Step-by-step explanation

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PRECAL please help me I’m stuck I don’t know where to begin? I need to pass

elixir [45]

$\text{Consider the limit}\\
\\
\underset{x\rightarrow -\infty}{\lim}f(x)=-\infty\\
\\
\text{It implies that as the value of x is decreasing to very large to reach}\\
\text{negative infinity, the value of the function f(x) is also approching to }\\
\text{the value negative infinity.}$

$\text{On the coordinate axis, we know that }-\infty \text{ occur when we move}\\
\text{to the left on x-axis without reaching a maximum.}\\
\\
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A. The graph falls on the left side.

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4 years ago

Find the volume and surface area of the composite figure. Give four answer in terms of pi

Gre4nikov [31]

Answer:

Step-by-step explanation:

Volume = Volume of cylinder + Volume of semi sphere

= pi*r^2*h+(2/3)*pi*r^3

=pi*(4*12+16/3)=pi*53.3

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3 years ago

vanesa multiplies two integers. When she adds the product to 4, the sum is 0. What can you say about the two integers

Lelu [443]

The Integers Are Positive They Are Not Negative Numbers. If It Was Negative It Would Be -2,-3,-4. While If It's Positive It Should Be 0,1,2,3,4 And So On.

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3 years ago

One side of triangle twice the length of the shortest side and the 3rd side 14 more feet than length of shortest side, find dime

kifflom [539]

Let's say the sides are "a" first one, "b" second one and "c" the third one

ok, let's say the shortest is "a"
and let's say "b" is -> " twice the length of the shortest side"
so b = 2a

and let's say "c" is -> "3rd side 14 more feet than length of shortest side"
so c = a + 14

we know the perimeter ( sum of all sides ) is 154

 $\bf \begin{array}{llll}
a&b&c\\
&\downarrow&\downarrow \\
&2a&a+14\\
\downarrow &\downarrow &\downarrow \\
\end{array}\\
\ a+b+\ c=154\\\\
a+(2a)+(a+14)=154$

solve for "a"

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3 years ago

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Bas_tet [7]

In the problem, I will use I as the item.

i+(i×.05)

Make sure you do the parentheses first ;)

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