Question

One side of triangle twice the length of the shortest side and the 3rd side 14 more feet than length of shortest side, find dimensions if perimeter is 154 feet for all 3 sides

Answer 1

Let's say the sides are "a" first one, "b" second one and "c" the third one

ok, let's say the shortest is "a"
and let's say "b" is -> " twice the length of the shortest side"
so b = 2a

and let's say "c" is -> "3rd side 14 more feet than length of shortest side"
so c = a + 14

we know the perimeter ( sum of all sides ) is 154

$\bf \begin{array}{llll} a&b&c\\ &\downarrow&\downarrow \\ &2a&a+14\\ \downarrow &\downarrow &\downarrow \\ \end{array}\\ \ a+b+\ c=154\\\\ a+(2a)+(a+14)=154$

solve for "a"