Answer:
17 minutes i had this same answer and question 2day, so ur lucky.
Step-by-step explanation:
The initial solution most people will think of is to use the fastest person as an usher to guide everyone across. How long would that take? 10 + 1 + 7 + 1 + 2 = 21 mins. Is that it? No. That would make this question too simple even as a warm up question.
To reduce the amount of time, we should find a way for 10 and 7 to go together. If they cross together, then we need one of them to come back to get the others. That would not be ideal. How do we get around that? Maybe we can have 1 waiting on the other side to bring the torch back. Ahaa, we are getting closer. The fastest way to get 1 across and be back is to use 2 to usher 1 across. So let's put all this together.
1 and 2 go cross
2 comes back
7 and 10 go across
1 comes back
1 and 2 go across (done)
Total time = 2 + 2 + 10 + 1 + 2 = 17 mins
Answer:
Step-by-step explanation:
Firstly,we need to find the mean, median and mode to enable us know the type of distribution it exhibit.
Mode-data with the highest frequency that is data that has the highest repetition which is 59.
Median-the middle data which is 75.
Mean-average of the data that is addition of the data divided by 25 which gives 75.4 approximately equals to 75
Distribution is unimodal symmetric if it has one clear peak(one mode) and mean = median , so Option A is right
Distribution is skewed left if the mean is less than median and the mode is less than the median that is mean is less than the median, and they are both less than the mode. So option B is wrong.
A distribution is uniform if all outcomes are likely to be the same,it is usually a rectangular shaped distribution. So option C is wrong
A distribution is bimodal if it has two modes. This means that there are two data values that tie for having the highest frequency but as for this data we have only one data with the highest frequency so option D is wrong
Option A is correct
Its 360 beacuse u multiply all of those numbers
Answer:
Answer : D
Step-by-step explanation:
A school has two kindergarten classes. There are 21 children in Ms. Toodle's kindergarten class. Of these, 17 are "pre-readers" children on the verge of reading. There are 19 children in Mr. Grimace's kindergarten class. Of these, 13 are pre-readers. Using the plus four confidence interval method, a 90% confidence interval for the difference in proportions of children in these classes that are pre-readers is â0.104 to 0.336.
Which of the following statements is correct?
A) This confidence interval is not reliable because the samples are so small.
B)This confidence interval is of no use because it contains 0, the value of no difference between classes.
C)This confidence interval is reasonable because the sample sizes are both at least 5.
D) This confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population.
The Answer is D - This confidence interval is not reliable because these samples cannot be viewed as simple random samples taken from a larger population.
In this setup, all the students are already involved in the data. This is not a sample from a larger population, but probably, the population itself.
If the lines are parallel, they have no solutions because they never touch
