Answer: She had left 54% of the money which is $1620.
Step-by-step explanation:
40% of $3000 = $1200
15% of $1200 = $180
$3000 - ($1200 + $180)
$3000 - $1380 = $1620
$1620 is the money she had left.
$1620 is 54% of $3000
She had 54% left of the money.
Hope that helped~!
Answer:
Step-by-step explanation:
In the diagram shown, the measure of angle 1 is oppositely directed to angle 2 and oppositely directed angles are equal.
Hence <1 = <3
Given < 1 = 3x-1 and <3 = 2x+9
Hence 3x-1 = 2x+9
collect like terms
3x-2x = 9+1
x = 10°
Since <1 = 3x-1
on substituting x = 10
<1 = 3(10)-1
<1 = 30-1
<1 = 29°
<1+<2 = 180 (angle on a straight line)
29+<2 = 180
<2 = 180-29
<2 = 151°
Similarly, on substituting x = 10 into <3
<3 = 2x+9
<3 = 2(10)+9
<3 = 20+9
<3 = 29°
<3+<4 = 180 (angle on a straight line)
29+<4 = 180
<4 = 180-29
<4 = 151°

Given:
population mean, μ =135
population standard deviation, σ = 15
sample size, n = 19
Assume a large population, say > 100,
we can reasonably assume a normal distribution, and a relatively small sample.
The use of the generally simpler formula is justified.
Estimate of sample mean

Estimate of sample standard deviation


to 5 decimal places.
Thus, using the normal probability table,





Therefore
The probability that the mean weight is between 125 and 130 lbs
P(125<X<130)=0.0731166-0.0018308
=
0.0712858
A
If you put them all into decimal form you get .1, .3, .9
Answer:
m<GFA = 110
Step-by-step explanation:
1. ABCD - parallelogram Definition of a parallelogram
(AB ll CD) (AD ll BC)
2. m<B + m<C = 180 Consectuive angles in a
110 + m<C = 180 parallelogram are supplementary
m<C = 70
3. m<GCB = 1/2 m<C Definition of angles bisector
m<GCB = 70
4. m<B = m<D = 110 Opposite angles in a
parrallelogram are congruent
5. m<CDG = 1/2 m<D Defintion of an angle bisector
m<CDG = 55
6. m<GCB+m<CDG+m<CGD=180 Sum of anlges in a triangle (ΔCDG)
70 + 55 + m<CGD = 180
125 + m<CGD = 180
m<CGD = 55
7. m<CGD + m<DGF = 180 Linear pair, supplmentary angles
55 + m<DGF = 180
m<DGF = 125
8. m<C = m<A = 70 Opposite angles in a paralellogram
are congruent
9. m<ADG = 1/2m<D Definiton of an angle bisector
m<ADG = 55
10.m<ADG+m<DFG+m<GFA+m<A=360 Sum of angles in quadrilateral
55 + 125 + m<GFA + 70 = 360 DGFA
m<GFA + 250 = 360
m<GFA = 110