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Kamila [148]
3 years ago
8

Directions: Graph each equation by using the y-intercept and slope( make sure too show your work)

Mathematics
1 answer:
vova2212 [387]3 years ago
4 0

Given:

The equation of a linear function is:

y=-\dfrac{2}{3}x-1

To find:

The y-intercept and slope of the given equation, then draw the graph of the equation.

Solution:

Slope intercept form of a line is:

y=mx+b             ...(i)

Where, m is the slope and b is the y-intercept

We have,

y=-\dfrac{2}{3}x-1        ...(ii)

On comparing (i) and (ii), we get

m=-\dfrac{2}{3}

b=-1

Therefore, the y-intercept is -1 and the slope of the line is -\dfrac{2}{3}.

It means the graph intersect the y-axis at point (0,-1) and having slope -\dfrac{2}{3}. So, the graph of the equation is shown below.

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27. The average hourly wage of workers at a fast food restaurant is $7.25/hr
morpeh [17]

Answer:

0.0668 = 6.68% probability that the worker earns more than $8.00

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The average hourly wage of workers at a fast food restaurant is $7.25/hr with a standard deviation of $0.50.

This means that \mu = 7.25, \sigma = 0.5

If a worker at this fast food restaurant is selected at random, what is the probability that the worker earns more than $8.00?

This is 1 subtracted by the pvalue of Z when X = 8. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 7.25}{0.5}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% probability that the worker earns more than $8.00

8 0
3 years ago
To assess the precision of a laboratory scale, we measure a block known to have a mass of 1 gram. we measure the block n times a
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<span>n = 5 The formula for the confidence interval (CI) is CI = m ± z*d/sqrt(n) where CI = confidence interval m = mean z = z value in standard normal table for desired confidence n = number of samples Since we want a 95% confidence interval, we need to divide that in half to get 95/2 = 47.5 Looking up 0.475 in a standard normal table gives us a z value of 1.96 Since we want the margin of error to be ± 0.0001, we want the expression ± z*d/sqrt(n) to also be ± 0.0001. And to simplify things, we can omit the ± and use the formula 0.0001 = z*d/sqrt(n) Substitute the value z that we looked up, and get 0.0001 = 1.96*d/sqrt(n) Substitute the standard deviation that we were given and 0.0001 = 1.96*0.001/sqrt(n) 0.0001 = 0.00196/sqrt(n) Solve for n 0.0001*sqrt(n) = 0.00196 sqrt(n) = 19.6 n = 4.427188724 Since you can't have a fractional value for n, then n should be at least 5 for a 95% confidence interval that the measured mean is within 0.0001 grams of the correct mass.</span>
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