Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
Im not exactly sure but i think its about 12 inches
Answer:
-5120
Step-by-step explanation:
Replace the n in the formula by 6.
a6 = -5(4)^(6-1)
= -5 * 4^5
= -5120
Answer:
A.
Step-by-step explanation:
Given
Ratio = 3:5
Q = -14
S = 2
Required
Which solution uses 
From the given parameters;
Substitute the above values in
This gives:
<em>From the list of given options, only option A uses the given form of the formula...</em>
Answer:
15:12:16
Step-by-step explanation:
x:y= 5:4
y:z= 3:2
5×3= 4×3
3×4= 2×8
15= 12
12= 16
Therefore x:y:z can be shown as follows
= 15:12:16
