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3 years ago

If the area of the rectangle is 154 km2, then what is the value of the missing side?

Mathematics

2 answers:

KatRina [158]3 years ago

7 0

Area of a rectangle: length * width

You are given the width, 11 km, so plug in 11 for width and 154 for area in the formula for area of a rectangle and solve for length (x).

x * 11 = 154

rewritten as: 11x = 154

Divide both sides by 11.

x = 14

Your answer is C) 14 km.

user100 [1]3 years ago

3 0

Area =
L×B=154
L×11=154
L=154/11
L=14km

C)14km

Hope it helps

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Answer:

6050 square feet

Step-by-step explanation:

Based on the diagram attached, the area which the available fencing can enclose will measure X x Y feet. As the total length of fencing available is 220 feet, the fenced perimeter must equal 220 feet

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$Y = 220 - 2X$

Area of a rectangle is determined by multiplying the length of perpendicular sides:

$Area = X*Y$

$Area = X(220 - 2X)$

$Area = 220X - 2X^{2}$

The derivative of an equation determines the slope at any given point of that equation. At the maximum or minimum point of the equation, the slope will be zero. Therefore, differentiating the equation for area and equating it to zero will give the value of X where the area is maximum.

A simple variable can be differentiated using below concept:

$f(a) = a^{b}$

$f'(a) = ba^{b-1}$

Using the above concepts to differentiate Area and calculate X will give:

$Area = 220X - 2X^{2}$

$Area' = 220 - 4X = 0$

$X = 55$

Calculating Y:

$Y = 220 - 2X$

$Y = 220 - 2(55)$

$Y = 110$

Calculating Area:

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$Area = 55*110$

$Area = 6050\sqfeet$

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2 years ago

A sidewalk forms the diagonal of a square park. The sidewalk is 30 meters long. To the nearest tenth of a meter, how long are th

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<span> <span>We can use the Pythagorean Theorem (A² + B² = C²) to solve for the lengths of the sides. We know that the diagonal, C, is 30 meters long, so C² = 900 meters. We know that since the park is square, A² + B² = 2A² = 2B²

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Taking the square root of 450, we find that the lengths of A and B are roughly 21.2 meters.</span> </span>

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