Well, since it says it's congruent, it's congruent. EF overbar congruent to GH overbar.
Answer:
The usually speed of the bus is 50 miles/h.
Step-by-step explanation:
Let the usual speed of the bus be x mile/hour.
We know that
The bus travels 200 miles.
To reach its destination it takes time h
This week however the bus leaves at 5:40.
The bus late 40 minutes
Now the speed of the bus is = (x+10) miles/h
The new time to reach the destination is h
According to the problem,
⇒2(x²+10x)=200×10×3
⇒x²+10x = 3000
⇒x²+10x -3000=0
⇒x²+60x-50x-3000=0
⇒x(x+60)-50(x+60)=0
⇒(x+60)(x-50)=0
⇒x= -60,50
∴x=50 [since speed does not negative]
The usually speed of the bus is 50 miles/h.
Evaluation of the expression using order of operation gives 26/11.
How to evaluate the expression
Given 13 ÷(2.5-1-3).33 = 13 ÷ 33( 2 x 5 - 1 - 3)
To evaluate this expression we need to apply the order of operation rule, BODMAS or PEMDAS.
13 ÷(2.5-1-3).33 = 13 ÷ 33( 2 x 5 - 1 - 3) Evaluate multiplication
= 13 ÷ 33(10 - 1 - 3) Evaluate what is in the bracket
= 13 ÷ 33(6) Evaluate division
= 13/33 x 6
= 78/ 33 = 26/11
Therefore, evaluating the expression gives 26/11.
Learn more about the order of operation on:
brainly.com/question/28360611
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Answer:
-1723
Step-by-step explanation:
Evaluate 5 - t^3 where t = 12:
5 - t^3 = 5 - 12^3
12^3 = 12×12^2:
5 - 12×12^2
| 1 | 2
× | 1 | 2
| 2 | 4
1 | 2 | 0
1 | 4 | 4:
5 - 12×144
| 1 | 4 | 4
× | | 1 | 2
| 2 | 8 | 8
1 | 4 | 4 | 0
1 | 7 | 2 | 8:
5 - 1728
5 - 1728 = -(1728 - 5):
-(1728 - 5)
| 1 | 7 | 2 | 8
- | | | | 5
| 1 | 7 | 2 | 3:
Answer: -1723