Answer: The correct option is the first one.
Step-by-step explanation:
Let's define how to interpret each symbol:
x < a (x is strictly smaller than a, we graph this with an open circle at a, and an arrow to the left of a)
x > a (x is strictly larger than a, we graph this with an open circle at a, and an arrow to the right of a)
x ≥ a (x is larger than or equal to a, we graph this with a closed circle at a, and an arrow to the right of a)
x ≤ a (x is smaller than or equal to a, we graph this with a closed circle at a, and an arrow to the left of a)
In this case, we have the inequality:
x ≤ 15
Then to graph this we need a closed circle at 15, and an arrow to the left. The correct option is the first one.
Answer:
B. 6:00
Step-by-step explanation:
There are 60 minutes in one hour.
To calculate 40 minutes after 4:40, separate 40 minutes into two lots of 20 minutes.
⇒ 4:40 + 20 minutes = 5:00
⇒ 5:00 + 20 minutes = 5:20
Therefore, 40 minutes after 4:40 is 5:20
To calculate the time that 5:20 is 40 minutes before, add 40 minutes to 5:20
⇒ 5:20 + 40 minutes = 6:00
Therefore, the solution is option B. 6:00
To solve both of these expressions, we want to add or subtract from left to right.
For the first one, we can rewrite it as:
8-6-9
=2-9
=-7
The second one we can rewrite as:
5-7+9+8-4
=-2+9+8-4
=7+8-4
=15-4
=11
Angle D is 180° -75° -45° = 60°. Drawing altitude MX to segment DN divides the triangle into ΔMDX, a 30°-60°-90° triangle, and ΔMNX, a 45°-45°-90° triangle. We know the side ratios of such triangles (shortest-to-longest) are ...
... 30-60-90: 1 : √3 : 2
... 45-45-90: 1 : 1 : √2
The long side of ΔMDX is 10√3, so the other two sides are
... MX = MD(√3/2) = 15
... DX = MD(1/2) = 5√3
The short side of ΔMNX is MX = 15, so the other two sides are
... NX = MX(1) = 15
... MN = MX(√2) = 15√2
Then the perimeter of ΔDMN is ...
... P = DM + MN + NX + XD
... P = 10√3 +15√2 + 15 + 5√3
... P = 15√3 +15√2 +15 . . . . perimeter of ΔDMN
Given:
difference in the mean weight gain is 0.60 grams
standard deviation of the difference in sample mean is 0.305
68% confidence interval for the population mean difference is a) 0.305
0.60 <u>+</u> 1 * 0.305
0.60 + 0.305 = 0.905
0.60 - 0.305 = 0.295
95% confidence interval for the population mean difference is c) 0.61
0.60 <u>+</u> 2 * 0.305
0.60 + 0.61 = 1.21
0.60 - 0.61 = -0.01
