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Dafna1 [17]
2 years ago
9

The school that Michael goes to is selling tickets to a dance. On the first day of ticket sales the school sold 3 staff tickets

and 1 student ticket for a total of $38. The school took in $52 on the second day by selling 3 staff tickets and 2 student tickets. Find the price of a staff ticket and the price of a student ticket.
Mathematics
1 answer:
Minchanka [31]2 years ago
8 0

The price of a staff ticket and the price of a student ticket is $8 and $14

Given:

Day 1:

Number of staff tickets sold = 3

Number of students tickets sold = 1

Total revenue day 1 = $38

Day 2:

<em>Number of staff tickets sold</em> = 3

<em>Number of students tickets sold</em> = 2

<em>Total revenue day</em> 2 = $52

let

<em>cost of staff tickets</em> = x

<em>cost of students tickets</em> = y

The equation:

<em>3x + y = 38 (1)</em>

<em>3x + y = 38 (1)3x + 2y = 52 (2)</em>

subtract (1) from (2)

2y - y = 52 - 38

y = 14

substitute y = 14 into (1)

3x + y = 38 (1)

3x + 14 = 38

3x = 38 - 14

3x = 24

x = 24/3

x = 8

Therefore,

cost of staff tickets = x

= $8

cost of students tickets = y

= $14

Read more:

brainly.com/question/22940808

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Step-by-step explanation:

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Using the Empirical Rule, it is found that:

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------------

The Empirical Rule states that, in a <em>bell-shaped </em>distribution:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
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Item a:

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43.5 + 3(2.77) = 51.88

Within <em>3 standard deviations of the mean</em>, thus, approximately 99.7%.

-----------

Item b:

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Within 2<em> standard deviations of the mean</em>, thus, approximately 95%.

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Item c:

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43.5 + 2.77 = 46.27

Approximately 68% of the amounts fall between $40.73 and $46.27.

A similar problem is given at brainly.com/question/15967965

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