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Aleksandr [31]
3 years ago
13

Explain how you could solve the following using equal groups.

Mathematics
1 answer:
nignag [31]3 years ago
3 0

Answer:

6

Step-by-step explanation:

48/8=6

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Answer:

A.

Step-by-step explanation:

yan na yannnnnnnnnnnnnnnn

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Leigh has a piece of rope that is 6 2/3 feet long. How do you write 6 2/3 as a fraction greater than 1
aleksley [76]
20/3 - Take the 6 2/3, multiply the 6 and the 3 (6 x 3 = 18), then add the 2 (18 + 2 = 20). Put that number over the original 3 and you've got yourself a mixed number.
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License plates in a particular state display 4 letters followed by 2 numbers. How many different license plates can be manufactu
bezimeni [28]
Depends on how many cars your talking about.Be more descriptive.
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4 years ago
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Selena buys 4 peaches that weigh 1 pound in all. Each peach weigh the same amount. Peaches are on sale for $2.24 per pound. Writ
DENIUS [597]

Answer:

The required equation is

4p = 2.24

And p = 0.56  [ where p is in $]

Step-by-step explanation:

Given that Selena buys 4 peaches that weight 1 pound in all.

Peaches are on sale for $2.24 per pound.

Since the total weight of peaches is 1 pound.

So the price of 4 peaches is $2.24.

Let p be the price of 1 peaches.

Then the price of 4 peaches is $(4×p)

                                                  = $4p

According to the problem,

4p = 2.24

\Rightarrow p=\frac{2.24}{4}

⇒p=0.56      [ where p is in $]

The required equation is

4p = 2.24

And p = 0.56  [ where p is in $]

8 0
3 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It
Vilka [71]

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, \bar{x} = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}

We use one-tailed(left) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92

Now, z_{critical} \text{ at 0.05 level of significance } = -1.64

Since,  

z_{stat} < z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

8 0
3 years ago
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