1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Blababa [14]
3 years ago
13

in a recent year one United States dollar was equal to about 82 Japanese yen how many Japanese yen are equal to $1,00 $1,000 $10

,000
Mathematics
1 answer:
Yuki888 [10]3 years ago
5 0
In a recent year, one United States dollar was equal to about 82 Japanese. How many Japanese yen are equal $100?$1,000?$10,000 
<span>Given is: </span>

<span>1 USD = 82 Japanese Yen   </span>

<span>Conversion: </span><span>

1.  100 USD x 82 JY / 1 USD = 8, 200 Japanese Yen</span> <span>
2.  1000 USD x 82 JY / 1 USD = 82, 000 Japanese Yen</span> <span>
3.  10, 000 USD x 82 JY / 1 USD = 820, 000 Japanese Yen</span> 
You might be interested in
What is the volume of this sphere?
andriy [413]
V≈113.1
----------------
or 36pi cm^2
5 0
3 years ago
Read 2 more answers
For which rational expression is –2 an excluded value of x?
Kipish [7]

Answer:

option a is the answer

Step-by-step explanation:

put the value of x in each expression as x = -2

you'll see that in option a the expression becomes

\frac{x - 3}{ {x}^{2}  - 4}   =   \frac{ - 2 - 3}{ {( - 2)}^{2}  - 4}  \\  =  \frac{ - 5}{4 - 4} \\  =   \frac{ - 5}{0}

which is not defined. hence -2 is excluded value

5 0
3 years ago
Pls answer. how did you get it?​
ivann1987 [24]

Answer:

Lowest Price - Store B

Middle Price - Store C

Highest Price - Store A

Step-by-step explanation:

Store A Price - $22.50

25 x 0.1 = 2.5

25 - 2.5 = 22.5

Store B Price - $21.60

27 x 0.2 = 5.4

27 - 5.4 = 21.6

Store C Price - $22.1

26 x 0.15 = 3.9

26 - 3.9 = 22.1

5 0
3 years ago
Jen ran for 10 minutes with the speed of 6 mph and then walked for 30 minutes at a speed of 3 miles per hour. What is the total
MaRussiya [10]

Answer:

The total distance covered by Jen was 4 miles.

Step-by-step explanation:

The formula for the average speed is shown below:

speed = distance / time

In this question we need to find the distance covered, therefore we will adjust the formula as shown below:

distance = time*speed

We will need to convert the time from minutes to hours, we do that by dividing by 60.

The total distance covered by Jen is the sum of the distances on each stage of his course, therefore:

total distance = distance 1 + distance 2

Applying the correct formula:

total distance = (time1 * speed1) + (time2 * speed2)

total distance = [(10/60)*6] + [(30/60)*3]

total distance = [60/60] + [90/60] = 1 + 3 = 4 miles

THe total distance covered by Jen was 4 miles.

4 0
3 years ago
Read 2 more answers
Atwo digit postive number is such that the ones digit is 2.5 times ad much as the tens digit if the number obtained when the dig
Sholpan [36]

Answer:

25.

Step-by-step explanation:

We can write the expression as 10x + 2.5x    where x is the tens digit.

So reversed we have 25x + x.

- and  25x + x - (10x + 2.5x) = 27

22.5x - 9x = 27

13.5x = 27

x = 2 and 2.5x = 5.

So the number is 25.

5 0
3 years ago
Other questions:
  • Which is bigger 1/3 or 3/8?
    15·1 answer
  • Please help!<br><br> y - x = 4<br><br><br> y - x = 0<br><br><br> x = 2/5y
    5·1 answer
  • What is the remainder in the synthetic division problem below? 1/1 2 -3 3<br>​
    9·1 answer
  • 7/2,16/6 tell whether froms a proportion
    6·2 answers
  • Compute the amount of interest earned in the following simple interest problem. A deposit of 4,500 at 5% for 3 years
    9·1 answer
  • Which letter is a good estimation of 55 on the number line?<br> A) <br> B) <br> C) <br> D)
    12·2 answers
  • Help help this is 10 points
    13·1 answer
  • Pls pls help with math final !!
    11·1 answer
  • If f(x) = 3x-2 and g(x) =2x+1 find (f+g)(x)<br>A. 5x-1<br>B. 5x-3<br>C. x-1<br>D. x-3​
    7·1 answer
  • Help! Can’t figure out how to do this
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!