February because it is the least amount of numbers
Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
Answer:
(a×b)×c = 0 means that vector c parallel to vector (a×b). But because (a × b) ⊥ a and (a -b) ⊥ b so
c ⊥ a and c ⊥ b.
Hope this helps, have a nice day! :D
B if you’re doing distributive property
