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Sati [7]
3 years ago
5

Henry constructed Circle a with a radius of 10 units. He then created a sector as shown in the figure below period which of the

following expressions would help him find the area of the shaded sector

Mathematics
2 answers:
tino4ka555 [31]3 years ago
7 0
B. 240/360 (100pi)

1. 120°/360° = x/100pi (the area of the circle)
2. cross multiply
3. find an equal expression
VLD [36.1K]3 years ago
5 0

Answer:

\frac{120^{\circ}}{360^{\circ}} \times 100\pi

Step-by-step explanation:

Radius of Circle : 10 units

Measure of angle of given sector = 120°

Formula of area of sector = \frac{\theta}{360^{\circ}} \times \pi r^2

Substitute the values in the formula .

Area of sector = \frac{120^{\circ}}{360^{\circ}} \times \pi (10)^2

                        = \frac{120^{\circ}}{360^{\circ}} \times 100\pi

So, Option 2 is correct.

Hence the expression would help him find the area of the shaded sector  is \frac{120^{\circ}}{360^{\circ}} \times 100\pi

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Describe what a graph of xs 1 would look like. (Be sure to include whether dot is open or closed and state
insens350 [35]

Answer:

The graph would be a line starting at one and moving to the left infinitely. The dot would be closed.

6 0
2 years ago
Pls help soon:)
Tanzania [10]
Correct answers are:
(1) <span>28, 141 known cases
(2) 79913.71 known cases after six weeks (round off according to the options given)
(3) After approx. 9 weeks (9.0142 in decimal)

Explanations:
(1) Put x = 0 in given equation
</span><span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(0)
</span>y= 28, 141


(2) Put x = 6 in the given equation:
<span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(6)
</span>y= 79913.71

(3) Since
y= 28, 141 (1.19)^x
And y = <span>135,000

</span>135,000 = 28, 141 (1.19)^x
135,000/28, 141 = (1.19)^x

taking "ln" on both sides:
ln(4.797) = ln(1.19)^x

ln(4.797) = xln(1.19)
x = 9.0142 (in weeks)

5 0
3 years ago
hich statement best describes the domain and range of p(x) = 6–x and q(x) = 6x? p(x) and q(x) have the same domain and the same
Sati [7]

Answer:

p(x) and q(x) have the same domain and the same range.

Step-by-step explanation:

p(x) = 6-x and

q(x) = 6x

First of all, let us have a look at the definition of domain and range.

Domain of a function y =f(x) is the set of input value i.e. the value of x for which the function f(x) is defined.

Range of a function y =f(x) is the set of output value i.e. the value of y or f(x) for the values of x in the domain.

Now, let us consider the given functions one by one:

p(x) = 6-x

Let us sketch the graph of given function.

Please find attached graph.

There are no values of x for which p(x) is not defined so domain is All real numbers.

So, domain is (-\infty, \infty) or x\in R

Its range is also All Real Numbers

So, Range is (-\infty, \infty) or x\in R

q(x) = 6x

Let us sketch the graph of given function.

Please find attached graph.

There are no values of x for which q(x) is not defined so domain is All real numbers.

So, domain is (-\infty, \infty) or x\in R

Its range is also All Real Numbers

So, Range is (-\infty, \infty) or x\in R

Hence, the correct answer is:

p(x) and q(x) have the same domain and the same range.

4 0
3 years ago
If x =&gt; y and y =&gt; z, which statement must be true?
Kruka [31]

The operator \geq is transitive, which means exactly that

x \geq y,\quad y\geq z \implies x \geq z

That's the only thing you can deduce from your statement.

6 0
3 years ago
Please answer this below Question # 15
LiRa [457]

Answer:

c. \: 5x - 2y = 10 \\ \:  \:  \:  \:  \:  10x - 4y = 20 \\

7 0
2 years ago
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