m = (y2-y1)/(x2-x1)
m = (6-4)/(4-0)
m = 2/4
y = mx + c
6 = (2/4)(4) + c
c = 4
Thus, the equation is y = (2/4)x +4
Two hundred Eighty One Point One Twenty Five Thousandths.
Answer:
The width of the football field is 160 feet.
The length of the football field is 360 feet.
Step-by-step explanation:
Let w represent width of the football field.
We have been given that the length is 200 ft more than the width, so the length of the field would be
.
We are also told that the perimeter is 1,040 ft. We know that football field is in form of rectangle, so perimeter of field would be 1 times the sum of length and width. We can represent this information in an equation as:

Let us solve for w.






Therefore, the width of the football field is 160 feet.
Upon substituting
in expression
, we will get length of field as:

Therefore, the length of the football field is 360 feet.
Answer:
measure the distance between two points on the ground and then measure angles between the top
The answer would be 70 degrees.
In order to find this answer, we must first look at the cos value of an angle. The unknown angle here gives us an adjacent side of 3.4 and a hypotenuse of 10. Thus, we can use the following with cos.
Cos(A) = 3.4/10 or Cos(A) = .34
As a result, we can then use the arccos function to find the answer.
acrcos(.34) = A
70.12 = A
Then when we round, we'd get 70.