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Oduvanchick [21]
2 years ago
6

Triangles A and B are congruent. Find the perimeter of triangle A. Give your answer to 1 dp. 11cm A 19cm B Not drawn accurately.

​

Mathematics
1 answer:
ANEK [815]2 years ago
5 0

Answer:

P ≈ 45.51

Step-by-step explanation:

19cm is the hypotenuse (C)

11cm is the opposite (A)

 adjacent (B) missing

formula a² + b² = c²

So we need to find b which is b²= c² - a²

b² = (19)² - (11)² = 240

b  = square root of 240

b = 15.5

P = a+b+a2+b2

P ≈ 45.51

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J.c. Penny sells a timed watch for $139.99 that cost$89.97. J.C. Penny’s percent of markup based on the selling price is:
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So it cost them 89.97 and they're selling it for 139.99, the difference is 50.02.

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\bf \begin{array}{ccll}
amount&\%\\
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3 years ago
the length of a rectangle is 5 inches longer than twice the width and the area is 12 inches squared. Let l represent the length
svet-max [94.6K]

Answer:

Length = 8 inch , Width = \frac{3}{2} , This equation models the situation

Step-by-step explanation:

Given as ;

The Area of Rectangle is 12 inches²

The Length of Rectangle is 5 inches longer than twice the width

Let The Length = L inches

      The Width   = W inches

According to question ,

L = 5 + (2 × w )

∵ The Area of Rectangle = Length × width

Or, 12  inches²  = [ 5 + (2 × w ) ] ×  w

Or,  12  inches² = 5 w +2 w²

Or,  2 w² + 5 w  - 12 = 0

Or,   2 w² + 8 w  -3 w - 12 = 0

Or,  2 w (w +4) - 3 (w + 4) = 0

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So ,  w = -4 , and w = \frac{3}{2}

∴  Length = 5 + (2 × w ) =

   Length = 5 + (2 ×\frac{3}{2}  )  

so ,  L = 5 + 3 = 8

Hence Length = 8 inch , Width = \frac{3}{2}   This equation models the situation Answer

3 0
3 years ago
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