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algol13
3 years ago
11

Simplify 8(x-4)+3x-2

Mathematics
1 answer:
Advocard [28]3 years ago
3 0

Answer: 11x - 34


Step-by-step explanation:

8x-  32 + 3x - 2  Combine like terms

11x -34.    Is your answer

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Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI
cricket20 [7]

Answer:

The system has infinitely many solutions

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

  1. Switch any two rows
  2. Multiply a row by a nonzero constant
  3. Add one row to another

To solve the following system

\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}

Step 1: Transform the augmented matrix to the reduced row echelon form

\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

The reduced row echelon form of the augmented matrix is

\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]

which corresponds to the system

\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}

The system has infinitely many solutions.

\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}

7 0
3 years ago
Record the product 23x79
Ber [7]
When I finished the work my product is 1,817
4 0
3 years ago
Read 2 more answers
John is making himself a lunch. He has three different soups to choose from, four kinds of soda, and three different kinds of fr
Levart [38]
<span>3*4*3=36 so the answer is 36</span>
3 0
3 years ago
A portion of a map with cities a and b is shown.The map uses a scale of 1 inch to 30 miles. A new map has a scale of 2 inches=15
Alina [70]

Answer:

22.5miles

Step-by-step explanation:

For Map 1;

1 inches = 30miles

For Map 2:

2 inches = 15miles

1 inches = x

2x = 1 *15

x = 15/2

x = 7.5miles

This means that 1 inch represents 7.5miles on Map 2'

The distance between the two cities in miles = 30miles - 7.5miles

The distance between the two cities (in miles) = 22.5miles

3 0
3 years ago
Help!
Bezzdna [24]

Answer:

The answer is c = 2 + 3d .

Step-by-step explanation:

It is given that a cab ride cost $2 which is a fixed amount and charges additional $3 per mile. So you have to make an equation of c in terms of d :

Let c be the cost,

Let d be the distance,

c = 2 + 3d

3 0
3 years ago
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