Answer:
The answer to the question is;
The number of papers expected to be handed in before receiving each possible grade at least once is 14.93.
Step-by-step explanation:
To solve the question , we note that it is a geometric distribution question which have equal probabilities and therefore is a form of Binomial distribution with Bernoulli trials, where we are conducting the trials till we have r successes
Since we have r = 6, we will have to find the expected value of the number of trials till the nth paper handed in receives a previously awarded grade.
We therefore have,
The Probability that out of six papers turned 5 are different scores is given by
P(Y=5) = p'= q⁵p = (1-p)⁵p = 3125/46656
Therefore p' = the probability of receiving different grades once then the expected value is given by
E(X) = 1/p' = 46656/3125 = 14.93.
Answer: 
Step-by-step explanation:
1. You know that the force acting on the object varies directly with the object's acceleration. Then, by definition, you have:
Where 
is the force acting on the object, 
is the object's acceleration and 
is the constant of proportionality.
2. Keeping this on mind, you can calculate the constant of proportionality by substituting 
and 
into the equation and solving for :
3. Now, you can calculate the force when the acceleration of the object becomes 5 m/s², as following:
3. The result is:
It would be greater than three because it is addition and when you add it is to increase not decrease. good luck!
Answer:
g
Step-by-step explanation:
