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Vika [28.1K]
3 years ago
5

(x+8)-14=-15 what is the solution to the equation

Mathematics
2 answers:
Artist 52 [7]3 years ago
3 0
(x+8)-14=-15 \\ \\ x+8=-15+14 \\ \\ x+8=-1 \\ \\ x=-1-8 \\\\ \boxed{x=-9}
cricket20 [7]3 years ago
3 0
(x + 8) - 14 = -15

*add 14 to both sides

(x + 8) = -15 + 14 = -1

*subtract 8 from both sides

x = -1 - 8 = -9

x = -9
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The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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