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NARA [144]
3 years ago
6

Solve by substitution x-y=-11 y+7=-2x

Mathematics
1 answer:
Bess [88]3 years ago
4 0

x - y = - 11   .............( 1 )

y + 7 = - 2x ...............( 2 )

from equation ( 1 )

x - y = - 11

x   = -11 + y  ...........( 3)      

putting x in equation  ( 2 )

y + 7 = - 2 x  

y  + 7 = -2 ( -11 + y )             y + 7 = 22 - 2 y                       y + 2 y =22 - 7            

3 y = 15                  y = 15 / 3

putting value of y in equation 3

x   = -11+ ( 13 /5 )                       x = -33 /3 + 15 / 3         ( l.c.m)

x  = -17 / 5                      

check      

x = -11 + y

- 17 / 5 = -11 + 13 / 5

-17 /5   = -17 / 5

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A guy wire is attached to the top of a radio antenna and to a point on horizontal ground that 40 m from the base of the antenna.
frutty [35]

Answer:

The length of the wire is 76.19 m.

Step-by-step explanation:

It is given that a guy wire is attached to the top of a radio antenna and to a point on horizontal ground that 40 m from the base of the antenna.

It means base of the right angled triangle is 40 m.

The wire makes an angle of 58deg 20min with the ground.

1 degree = 60 min

Using this conversion convert the given angle in degree.

58^{\circ}20'=58^{\circ}\frac{20}{60}^{\circ}=58\frac{1}{3}^{\circ}=\frac{175}{3}^{\circ}

In a right angled triangle

\cos \theta=\frac{adjacent}{hypotenuse}

\cos (\frac{175}{3}^{\circ})=\frac{40}{hypotenuse}

0.525=\frac{40}{hypotenuse}

hypotenuse=\frac{40}{0.525}

hypotenuse=76.190

Therefore the length of the wire is 76.19 m.

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3 years ago
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James measured a piece of construction paper to be 6 3/4 inches wide and 9 2/3 inches long. What is the area of the piece of con
ivolga24 [154]

Answer:

The area of the piece of construction paper is \frac{261}{4} inches^2

Step-by-step explanation:

Length of construction paper =6 \frac{3}{4} inches

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Width of construction paper = 9 \frac{2}{3} inches

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Area of construction paper =Length \times Width

Area of construction paper = \frac{27}{4}  \times \frac{29}{3}

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Hence the area of the piece of construction paper is \frac{261}{4} inches^2

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