Calculate for the mean/ average of the given numbers:
μ = (1 + 2 + 3 + 4 + 5) / 5 = 3
Then, we calculate for the summation of the squares of differences of these numbers from the mean, S
S = (1 - 3)² + (2 - 3)² + (3 - 3)² + (4 - 3)² + (5 - 3)²
S = 10
Divide this summation by the number of items and take the square root of the result to get the standard deviation.
SD = sqrt (10 / 5) = sqrt 2
SD = 1.41
Thus, the standard deviation of the given is equal to 1.41.
Answer:
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Step-by-step explanation:
essays= x
quizzes=y
2x=60
x=30 1 essay per 30 days
4y=40
y=10 1 quiz every 10 days
120/30=4
120/10= 12
so 4 essays and 12 quizzes in 120 days
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Answer: 0.951%
Explanation:Note that in the problem, the scenario is either the adult is using or not using smartphones. So, we have a yes or no scenario involved with the random variable, which is the number of adults using smartphones. Thus, the number of adults using smartphones follows the binomial distribution.
Let x be the number of adults using smartphones and n be the number of randomly selected adults. In Binomial distribution, the probability that there are k adults using smartphones is given by

Where p = probability that an adult is using smartphones = 54% (since 54% of adults are using smartphones).
Since n = 12 and k = 3, the probability that fewer than 3 are using smartphones is given by

Therefore, the probability that there are fewer than 3 adults are using smartphone is 0.00951 or
0.951%.
<u>Answer</u>:- No.
<u>Explanation</u> :-
<u>Substitute these numbers in pythagoras theorem to check if the set of numbers is a pythagorean triplet.</u>
<u>Pythagoras theorem</u> :- sq. of hypotenuse (longest side) is equal to the sum of sq.s of other two sides.
<u>Here</u>,
hypotenuse = 12 (as it is the longest side)
and other two sides are 6 and 9.
----> 6^2 + 9^2 = 12^2
----> 36 + 81 = 144
----> 117 = 144
Since, LHS is not equal to RHS, this set of numbers is not a pythagorean triplet.
Answer:
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