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umka2103 [35]
3 years ago
13

Larry Lazy purchased a one year membership at a local fitness center at the beginning of the year. It cost him $150. He goes twi

ce a week for the first three months (13 weeks) of the year, but then goes only once a month for the rest of the year.
How much does each visit to the center cost? $  per visit.
If he continued going twice a week all year, how much would each visit cost? $  per visit.
Mathematics
2 answers:
Papessa [141]3 years ago
7 0
$4.05 per visit
if he continued going to the gym twice a week all year would be $2.88 per visit.
Lerok [7]3 years ago
4 0
Larry goes twice a week in the first 3 months and then once a month for the rest of the 9 months.

Total number of times he went = 13 x 2  + 9 = 35

He went a total of 35 times in the year.

The membership for the year cost him $150, to calculate the cost of one visit, we divide the cost with the number of visits.

150 ÷ 35 = $4.29 (nearest hundredth)

It costs him $4.29 each visit to the centre.

If he goes twice a week for the whole year, he would have gone for 52 x 2 times since there are 52 weeks in a year.

52 x 2 = 104 

He would have gone for 104 times. 

To find the cost of each visit, we divide the $150 membership with 104 times.

150 ÷  104 = $1.44

Each visit would cost him $1.44.

----------------------------------------------------------------
Answer: (a) $4.29 (b) $1.44
----------------------------------------------------------------
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Evaluate the integral to solve for y :

\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt

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Use the other known value, f(2) = 18, to solve for k :

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3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1

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2 years ago
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It is given that the dashed line segments form 30 degree angles.

We have rotated the hexagon about O to map PQ to RF. Since P and R are consecutive vertices, therefore the angle between them is 60 degree.

The vertex R is immediate next to the vertex P in clockwise direction.

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8 0
3 years ago
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AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

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To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

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