a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

Evaluate the integral to solve for y :



Use the other known value, f(2) = 18, to solve for k :

Then the curve C has equation

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

The slope of the given tangent line
is 1. Solve for a :

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).
Decide which of these points is correct:

So, the point of contact between the tangent line and C is (-1, -3).
Answer:
The correct option is (D).
Step-by-step explanation:
It is given that GIKMPR is regular hexagon. It means it has 6 vertices.
Since the central angle is 360 degree. Therefore the central angle between two consecutive vertices is

It is given that the dashed line segments form 30 degree angles.
We have rotated the hexagon about O to map PQ to RF. Since P and R are consecutive vertices, therefore the angle between them is 60 degree.
The vertex R is immediate next to the vertex P in clockwise direction.
So if we rotate the hexagon at 60 degree clockwise about O, then we can maps PQ to RF.

Therefore we can also rotate the hexagon at 300 degree counterclockwise about O, then we can maps PQ to RF.
Therefore option D is correct.
Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is
is correct answer
Therefore
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
( using the property
)
( using the property 
( combining the like powers )
( using the property
)

( using the property
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is
is correct answer
Answer:
See step-by-step explanation
Step-by-step explanation:
Question 3: (4, -3)
Solving through elimination: Multiply the first equation by -3.
-3x+6y=-30
3x-5y = 27
Add. The x drops out.
y= -3
Substitute -3 in for y.
x-2y=10
x-2(-3)=10
x+6=10
x=4
Question 4: (2,5)
Solve through elimination: Multiply the second equation with 3.


3/2= 6/4
15/4x=7.5
x=2
3/2 (2) + y = 8
3+ y =8
y=5
Question 5: (6,4)
Use your graph to graph.

Slope of -1/3
Y-intercept of 6 (0,6)
X-intercept of 18 (18,0)

Slope of 3/2
Y-intercept of -5 (0,-5)
X-intercept of
(
Question 6: (5, -7)




Solve by substitution:
Words of encouragement:
Good luck!
9 (2x-5) =
Remember to look at words that indicate an operation is to take place (Eg: "times" (x) "less than" (-) "Twice x" (2x))
Hope this helps!