For this case we have the following equation:
w = F • PQ
Where,
w: work done
F: is the force vector
PQ: is the vector of the direction of movement.
Rewriting the equation we have:
w = || F || • || PQ || costheta
Substituting values:
w = (60) * (100) * (cos (45))
w = (60) * (100) * (root (2) / 2)
w = 4242.640687 lb.ft
Answer:
The work done pushing the lawn mower is:
w = 4242.6 lb.ft
Answer:
Simplify the expression; 2^3 x 2^2
<u>A. 2^5
</u>
B. 4^6
C. 4^5
D. 2^6
Step-by-step explanation:
You add the powers together since you are multiplying.
Answer: Both families were travelling at the same speed/rate of 1mile/0.65mins or 1mile/0.01hr.
Step-by-step explanation: Speed of Houck family's train = 552m/6hrs
speed of Robert family's train = 744m/8hrs.
Therefore considering Houck speed,
552miles = 6hours
1mile = (6 x 60)/552
= 360/552
= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr
For Robert
744miles = 8hours
1mile = ( 8 x 60 )/744
= (480/744)minutes
= 0.645
= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr
Conclusion: Both families were travelling at the same speed/rate.
To get that minutes in hour, just divide by 60 to get concert to hours.
Answer:
Step-by-step explanation:
Let (x,y) be midpoint of P(3,4) & Q(5,−2)
Midpoint formula for two points (a,b) and (c,d) is
(x,y) =(
2
a+c
,
2
b+d
).
x=
2
3+5
=4
y=
2
4−2
=1
∴ (x,y)=(4,1)
Answer: i think its B
Step-by-step explanation:
