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anyanavicka [17]
3 years ago
7

3 times the sum of x and 6 equals 10 times the difference of x and 1.

Mathematics
1 answer:
o-na [289]3 years ago
4 0
3(x + 6) = 10(x - 1)
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One half of a number less than six is greater than or equal to ten
Colt1911 [192]

Answer:

5 is half of ten hope it helps

3 0
3 years ago
Chris made $378 for 18 hours of work.
andre [41]

Answer:

$147

Step-by-step explanation:

378 / 18  = 21

1 hour of work = $21

7 hours of work = $21 * 7 = $147

5 0
3 years ago
A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover
riadik2000 [5.3K]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

\left[\begin{array}{cccc}T&H&S&P\\S&600&1300&2000\\L&400&300&400\end{array}\right] = A.

In the above matrix A, the columns refers the three type of books and the rows refers the from which stores the books are been sold.

The numbers represents the corresponding sales in the month of January.

The sale is same for the 6 months.

Hence, 6A = \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right]. This matrix 6A represents the total sales over the 6 months.

(b)

If we denote the books in stock at the starting of January by B, then

B = \left[\begin{array}{cccc}T&H&S&P\\S&1000&3000&6000\\L&1000&6000&3000\end{array}\right].

Each month, the chain restocked the stores from its warehouse by shipping 500 hardcover, 1,400 softcover, and 1,400 plastic books to San Francisco and 500 hardcover, 500 softcover, and 500 plastic books to Los Angeles.

If we represent the amount restocked books at the end of each month by another matrix C, then

C = \left[\begin{array}{cccc}T&H&S&P\\S&500&1400&1400\\L&500&500&500\end{array}\right].

This restocking will be done for 5 times before the end of June.

If there would be no sale, then the stock would be

B + 5C = \left[\begin{array}{cccc}T&H&S&P\\S&1000+2500&3000+7000&6000+7000\\L&1000+2500&6000+2500&3000+2500\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right].

Since, the total sale is given by 6A, at the end of June, the inventory in each store can be shown as following,

B+5C-6A \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right] - \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&-100&2200&1000\\L&1100&6700&3100\end{array}\right]

6 0
3 years ago
Help, I don’t know how to solve this.
NNADVOKAT [17]

Answer: Angles ABD and BAD (B)

Step-by-step explanation: Angles ABD BAD are not congruent angles, since they are the same angles.

Congruent angles are angles that both measure the same in degrees.

In this case, B is your correct answer since that answer has the same angle and not comparing any 2 angles, just the same one.

Hope This Helped, Have A Great Day!

3 0
2 years ago
the perimeter of a rectangle swimming pool is 486 feet. The width of the pool is 35 feet less than the length. Find the length a
statuscvo [17]

Answer:

Length: 139 feet

Width: 104 feet

Step-by-step explanation:

The formula for the perimeter of a rectangle can be given by P = 2l + 2w. We are given the perimeter of the pool along with the width.

P = 486

w = l - 35

From here, all we have to do is plug back into the original formula:

486 = 2l + 2(l - 35)

Which can be further simplified as:

486 = 2l + 2l - 70

486 = 4l - 70

From here, all we have to do is add 70 to both sides of the equation and divide by four:

556 = 4l

139 = l

To make sure that this answer is accurate, we can find that the width of the rectangle should then be 104 (given by 139 - 35). All we have to do is plug back into the original equation:

P = 2l + 2w

P = 2(139) + 2(104)

P = 278 + 208

P = 486

And the substitution works, so the length of the rectangle would be 139 feet and the width would be 104 feet.

5 0
2 years ago
Read 2 more answers
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