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maw [93]
2 years ago
5

If f(x) = 3x2 - 2x + 1, then find f(0)

Mathematics
1 answer:
MissTica2 years ago
3 0

f (0) = 3.(0)(0) - 3.(0)

      = 0

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Step-by-step explanation:

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Can someone plz help me with questions 1-4?
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For question one, he still owes his uncle $10 because he only payed him $200. So no it is not settled.

(sorry dont have much time to do #2)

#3)  Archibald payed off $200 of his debt only to have $10 left over to pay. $200-$210=-10

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Evaluate the definite integral from pi/3 to pi/2 of (x+cosx) dx
Vadim26 [7]

Answer:

\displaystyle \int\limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} {(x + \cos x)} \, dx = \frac{5 \pi ^2}{72} + 1 - \frac{\sqrt{3}}{2}

General Formulas and Concepts:

<u>Calculus</u>

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:                                                           \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                 \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Addition/Subtraction]:                                                   \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

\displaystyle \int\limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} {(x + \cos x)} \, dx

<u>Step 2: Integrate</u>

  1. [Integral] Rewrite [Integration Property - Addition/Subtraction]:           \displaystyle \int\limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} {(x + \cos x)} \, dx = \int\limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} {x} \, dx + \int\limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} {\cos x} \, dx
  2. [Left Integral] Integration Rule [Reverse Power Rule]:                           \displaystyle \int\limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} {(x + \cos x)} \, dx = \frac{x^2}{2} \bigg| \limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} + \int\limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} {\cos x} \, dx
  3. [Right Integral] Trigonometric Integration:                                             \displaystyle \int\limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} {(x + \cos x)} \, dx = \frac{x^2}{2} \bigg| \limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} + \sin x \bigg| \limits^{\frac{\pi}{2}}_{\frac{\pi}{3}}
  4. Integration Rule [Fundamental Theorem of Calculus 1]:                         \displaystyle \int\limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} {(x + \cos x)} \, dx = \frac{5 \pi ^2}{72} + \bigg( 1 - \frac{\sqrt{3}}{2} \bigg)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

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mel-nik [20]
You must first set up an equation for this problem.  Your equation is 8+3x=128.  If we subtract 8 from each side we get 3x=120.  If we then divide both sides by 3 we get x=40.  Therefore your number is 40 because 8+3*40=128.
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