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umka2103 [35]
3 years ago
8

Can someone help? anyone who's taking like geometry?

Mathematics
1 answer:
dangina [55]3 years ago
4 0
The triangles are similar so corresponding sides will be in ratio. The first triangle has sides of 2, 4, and 6. The second triangle has a largest side of 24. You are asked to find the perimeter of the second triangle. 
The largest side of the first triangle is 6 and the largest side of the second triangle is 24. This is a ratio of 6:24 which can be reduced to 1:4.
Each side of the second triangle is 4 times as large as the corresponding side of the first triangle.
Now we can calculate the other 2 sides.
2 x 4 = 8
4 x 4 = 16
The three sides are 8, 16 and 24
Perimeter of this triangle is 8 + 16 + 24 = 48
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mixas84 [53]

Answer:

1/5

Step-by-step explanation:

up 1, right 5

5 0
3 years ago
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Given the points P(2,-1) and Q(-9,-6), what are the coordinates of the point on directed line segment PQ that partitions PQ in t
gayaneshka [121]

ANSWER

( -  \frac{23}{5} , - 4)

EXPLANATION

Given the points P(2,-1) and Q(-9,-6),the coordinates of the point that partition the directed line segment PQ in the ratio 3:2 is given by

x = \frac{ mx_2+nx_1}{m + n}

y= \frac{ my_2+ny_1}{m + n}

Where m=3 and n=2

x = \frac{ 3 ( - 9)+2(2)}{3+ 2}

x = \frac{  - 23}{5}

y= \frac{ 3( - 6)+2( - 1)}{3 + 2}

y= \frac{  - 20}{5}  =  - 4

The point is

( -  \frac{23}{5} , - 4)

4 0
3 years ago
Someone please help me
Anika [276]

Answer:

A

Step-by-step explanation:

Given

a = \frac{1}{x} - \frac{1}{y} = \frac{y-x}{xy} ← as a single fraction

Thus

\frac{1}{a} = \frac{1}{\frac{y-x}{xy} } = \frac{xy}{y-x} → A

6 0
3 years ago
I have a few questions:
inn [45]
Hello,
Please, see the attached files.
Thanks.

3 0
3 years ago
Please help me! I'm spending 50 points on this question and my last two questions never even got answered!
Verdich [7]

Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

\frac{3x^2 + x^4 + 2}{4x - 3}

4x - 3 makes up our denominator, the bottom part of the fraction. So

4x - 3 = 0

4x = 3

x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

8 0
3 years ago
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