
Step-by-step explanation:
Hello, please consider the following.
Using Maclaurin series expansion, we can find an equivalent of sin(x) in the neighbourhood of 0.

Then,

Thank you
Answer:
i am in middle school but i know it Yx6
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
This is just a general property to know, I don't want to prove it LOL
Y=mx+b
y=2x+b
then substitute x and y
3=2(3) + b
3= 6 + b
b=-3
y=2x-3
Since a serving is 1/2 cup and he needs 72 servings you can multiply 72 by 1/2 and find out that he needs to make 36 cups of punch. Two cups is a pint so he needs (36 / 2) 18 pints of juice. He already has the 8 pints of pineapple juice so 18 - 8 leaves 10 pints of orange juice.