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3 years ago

Xf(3)+3f(x)=x+6 f(6)=?

Mathematics

1 answer:

TiliK225 [7]3 years ago

7 0

Answer: 36f/6f-1
solution: move all terms to left side and set equal to zero. then set each factor equal to zero.

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Y=-3 - x, how to draw the graph

adell [148]

Answer: See attachment below (graphing)

Step-by-step explanation:

INFORMATION:

The slope-intercept is when y=mx+b

mx=the slope

b=y-intercept

REPHRASE EQUATION:

y=mx+b

y=-3-x

y=(-1)x-3

CONCLUSION:

Slope=-1

Y-intercept=-3

Hope this helps!! :)

Please let me know if you have any questions

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3 years ago

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There are 45 students for 5 busses. What is the unit rate?

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For each bus there will be 9 students

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2 years ago

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A small jar of salsa contains 12 1/2 cup of salsa. A large jar of salsa contains 75 ounces. How many small jars of salsa is equa

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Step-by-step explanation:

75 divided by 12.5 equals 6 cups of salsa

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3 years ago

6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the

MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

$a_1$ the horizontal distance between the first observer and the ballonist

$a_2$ the horizontal distance between the second observer and the ballonist

$\alpha _1$ and $\alpha _2$ the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

$S=a*h$ (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

$S=S_1+S_2$ (equation 2)

$S_1=a_1*h$

But we can write $S_1$ in terms of $\alpha _1$ , like this:

$\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}$

And for $S_2$ will be the same:

$S_2=\frac{h^{2} }{\tan(\alpha _2)}$

Replacing in the equation 2:

$S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})$

And replacing in the equation 1:

$h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}$

So, we can replace all the known data in the last equation:

$h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft$

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0

3 years ago

At the dog park, there are several dogs with their owners. Counting heads, there are 20; counting legs, there are 62. How many d

Nataly_w [17]

There are 9 owners and 11 dogs
9×2=18
11×4=44
44+18=62

6 0

3 years ago

Xf(3)+3f(x)=x+6 f(6)=?​

Xf(3)+3f(x)=x+6 f(6)=?