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jarptica [38.1K]
2 years ago
6

Solve for x. 5 = 2x − 3

Mathematics
2 answers:
stepladder [879]2 years ago
8 0

Answer:

5 = 2x - 3 \\ 2x = 5 + 3 \\ 2x = 8 \\ x =  \frac{8}{2}  \\ x = 4

hope helpful <3"

Greeley [361]2 years ago
4 0

Answer:

-4

Step-by-step explanation:

2X= -5 -3

2X= -8

X= -8/2

X= -4

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seropon [69]

Answer:

Step-by-step explanation:

So the sign means that y has to be less than or equal to x plus 9

if you wanted an answer an example could be

y = 1

x = 10

this works because if implemented into the equation

1 ≤ 10 + 9 which is true

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a_sh-v [17]

Answer:

Step-by-step explanation:

In the first column, put days at the top and pounds at the bottom.

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How many places do you need to move the decimal to the left to write the
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Answer:

9

Step-by-step explanation:

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3 years ago
Choose the correct simplification of f^9 h^23/f^3 h^17
Tanzania [10]

Answer:

f6h40

Step-by-step explanation:

Step  1  :

           h23

Simplify   ———

           f3  

Equation at the end of step  1  :

         h23

 ((f9) • ———) • h17

         f3  

Step  2  :

Multiplying exponential expressions :

2.1    h23 multiplied by h17 = h(23 + 17) = h40

Final result :

 f6h40

4 0
3 years ago
"A rectangle has a height of 5 cm and its base is increasing at a rate" of 3/2 cm/min. When its area is 60 cm2, at what rate is
sukhopar [10]

Answer:

The diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

Step-by-step explanation:

Dimensions of the rectangle

Height = 5cm

Rate of base = 3/2 cm/min

Area = 60cm^2

We know the area of a rectangle of given by = base* Height

b*h = 60

b*5 = 60

b = 12cm

Applying Pythagoras theorem while drawing a diagonal to the rectangle

  b^2 +h^2 =  D^2\\

 5^2 +12^2 = 13^2

so our diagonal will be 13cm  

Upon differentiating the area of the rectangle  we get

b*h = A=60cm^2

using  the chain rule of differentiation

h*db/dt + b*dh/dt  = 0

b*dh/dt = -h*db/dt

12*dh/dt = -5*3/2

dh/dt = -5/8 cm//min

so the height of the rectangle is decreasing at the rate of -5/8cm/min

now we have all the measurements we need

b = 12 , db/dt = 3/2cm/min

h = 5 , dh/dt = -5/8 cm/min

b^2 +h^2  = D^2

Upon differentiating we get

2b*db/dt + 2h*dh/dt = 2D*dD/dt

b*db/dt + h*dh/dt = D*dD/dt

12*3/2 + 5*(-5/8) = 13*dD/dt

18 -25/8 = 13*dD/dt

\frac{144-25}{8} = 13*dD/dt

dD/dt = \frac{119}{104} cm/min

Therefore the diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

6 0
3 years ago
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