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3 years ago

7

A spinner has 3 equal sections labeled X, Y, and Z. Jinghua spins this spinner twice. Which represents all the possible outcomes

for Jinghua?
Select one:

XY, XZ, YX, YZ, ZX, ZY

XX, XY, XZ, YX, YY, YZ, ZX, ZY, ZZ

X, Y, Z

XX, YY, ZZ
acually anwser or i'll report u

1 answer:

gtnhenbr [62]3 years ago

7 0

Answer:

XX, YY, ZZ

Step-by-step explanation:

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Show that if X is a geometric random variable with parameter p, then

Lubov Fominskaja [6]

Answer:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

In order to find the expected value E(1/X) we need to find this sum:

$E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}$

Lets consider the following series:

$\sum_{k=1}^{\infty} b^{k-1}$

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

$\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}$ (a)

On the last step we assume that $0\leq r\leq b$ and $\sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}$ , then the integral on the left part of equation (a) would be 1. And we have:

$\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)$

And for the next step we have:

$\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}$

And with this we have the requiered proof.

And since $b=1-p$ we have that:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

4 0

3 years ago

A sno-cone machine priced at $139 is on sale for 20% off. What is the price of the sno-cone machine after the discount? *

lawyer [7]

So percents are just written as 20% = 0.2 so keep that in mind

139 divided by 0.2 is 95 , which would be the price after the discount :)

hope this helps!
give me brainliest

7 0

3 years ago

Please help!!! I will mark someone brainliest!

valina [46]

Answer:

a = 8, b = $\frac{3}{2}$

Step-by-step explanation:

Given the exponential function

f(x) = a $b^{x}$

To find a and b use the given coordinate points on the graph

Using (0, 8 ), then

8 = a $b^{0}$ [ $b^{0}$ = 1 ] , then

a = 8

f(x) = 8 $b^{x}$

Using (2, 18 ) , then

18 = 8b² ( divide both sides by 8 )

$\frac{18}{8}$ = b² , that is

b² = $\frac{9}{4}$ ( take the square root of both sides )

b = $\sqrt{\frac{9}{4} }$ = $\frac{3}{2}$

Thus

f(x) = 8 $(\frac{3}{2}) ^{x}$

3 0

2 years ago

WILL GIVE BRANLIEST!!! Pls help! Determine the coordinates of the point on the straight line y=3x+1 that is equidistant from the

iren [92.7K]

Let , coordinate of points are P( h,k ).

Also , k = 3h + 1

Distance of P from origin :

$d=\sqrt{h^2+k^2}$

Distance of P from ( -3, 4 ) :

$d=\sqrt{(h+3)^2+(k-4)^2}$

Now , these distance are equal :

$h^2+(3h+1)^2=(h+3)^2+(3h+1-4)^2\\\\h^2+(3h+1)^2=(h+3)^2+(3h-3)^2$

Solving above equation , we get :

$P=(\dfrac{16}{21},\dfrac{23}{7})$

Hence , this is the required solution.

6 0

3 years ago

1. Find the value of

spin [16.1K]

9514 1404 393

Answer:

-√5
3/5
-4/5

Step-by-step explanation:

The relevant relations are ...

sec = ±√(tan² +1)

cos = 1/sec

csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

8 0

2 years ago