Use the equation to answer the question. X^3=729. What

In a survey of a group of men, the heights in the 20-29 age group were normally distributed, with a mean of 67 inches and a s

liq [111]

Answer:

a) 20.33% probability that the participant is less than 64.5 inches.

b) 33.72% probability that the participant is more than 68.25 inches

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 67, \sigma = 3$

a.) Find the probability that the participant is less than 64.5 inches?

This is the pvalue of Z when X = 64.5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{64.5 - 67}{3}$

$Z = -0.83$

$Z = -0.83$ has a pvalue of 0.2033

20.33% probability that the participant is less than 64.5 inches.

b.) Find the probability that the participant is more than 68.25 inches?

This is 1 subtracted by the pvalue of Z when X = 68.25.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{68.25 - 67}{3}$

$Z = 0.42$

$Z = 0.42$ has a pvalue of 0.6628

1 - 0.6628 = 0.3372

33.72% probability that the participant is more than 68.25 inches

3 0

4 years ago

Please please help me

DanielleElmas [232]

Answer:

y = 105°

Step-by-step explanation:

In an isosceles trapezoid

• Any lower base angle is supplementary to any upper base angle

• The lower base angles are congruent

75 and x are supplementary, thus

x = 180° - 75° = 105°

x and y are lower base angles and congruent, so

y = x = 105°

8 0

3 years ago

Can anyone explain how to do this? Thanks!

BARSIC [14]

Hope this would help you

3 0

3 years ago

Graph the circle (x+6)^2 + (y+5)^2 =9

Andrei [34K]

Answer:

This a circle centered at the point $(-6,-5)$ , and of radius "3" as it is shown in the attached image.

Step-by-step explanation:

Recall that the standard formula for a circle of radius "R", and centered at the point $(x_0,y_0)$ is given by:

$(x-x_0)^2+(y-y_0)^2=R^2$

Therefore, in our case, by looking at the standard equation they give us, we extract the following info:

1) $R^2 = 9\,\,\,then\,\,\,R=3$ since the radius must be a positive number and ( $R=-3$ ) is not a viable answer.

2) $x_0=-6$ for ( $x-x_0$ ) to equal $(x+6)$

3) $y_0=-5$ for ( $y-y_0$ ) to equal $(y+5)$

Therefore, we are in the presence of a circle centered at the point $(-6,-5)$ , and of radius "3". That is what we draw as seen in the attached image.

5 0

3 years ago

Given f(x) = -x + 1, solve for x when f(x) = 0.

Ymorist [56]

Answer:

1

Step-by-step explanation:

0=-x+1

-x=-1

x=1

4 0

3 years ago