All categories

2 years ago

Use the equation to answer the question. X^3=729. What

Mathematics

1 answer:

vaieri [72.5K]2 years ago

8 0

Answer:

Step-by-step explanation:

You might be interested in

What number falls between 7 and 8 on the number line.

den301095 [7]

Answer:

the answer is 7.5

5 0

3 years ago

Read 2 more answers

Which of the following is a composite number? <br><br> A. 63<br> B. 19<br> C. 1<br> D. 0

Alexandra [31]

The composite number is A.63. 1 is neither a prime or composite. 19 is a prime. 0 is a trick honestly, it isn't a prime or a composite

6 0

3 years ago

the circumference of a circle is about 25.3 in find the area of the circle using 3.14 as an approximation for pie.Round your ans

sertanlavr [38]

<span>50.962 is answer m8t</span>

3 0

3 years ago

Attachment Mathswatch!!

inna [77]

Answer:

y=3x+1

Step-by-step explanation:

y=mx+c

Gradient is 3

Rise/run=3/1=3

Y intercept=1

y=3x+1

4 0

3 years ago

Read 2 more answers

Mathematical induction of 3k-1 ≥ 4k ( 3k = k power of 3 )

tresset_1 [31]

For making mathematical induction, we need:

a base case

An $n_0$ for which the relation holds true

the induction step

if its true for $n_i$ , then, is true for $n_{i+1}$

the relationship is not true for 1 or 2

$1^3-1 = 0 < 4*1$

$2^3-1 = 8 -1 = 7 < 4*2 = 8$

but, is true for 3

$3^3-1 = 27 -1 = 26 > 4*3 = 12$

<h3>induction step</h3>

lets say that the relationship is true for n, this is

$n^3 -1 \ge 4 n$

lets add 4 on each side, this is

$n^3 -1 + 4 \ge 4 n + 4$

$n^3 + 3 \ge 4 (n + 1)$

now

$(n+1)^3 = n^3 +3 n^2 + 3 n + 1$

$(n+1)^3 \ge n^3 + 3 n$

if $n \ge 1$ then $3 n \ge 3$ , so

$(n+1)^3 \ge n^3 + 3 n \ge n^3 + 3$

$(n+1)^3 \ge n^3 + 3 \ge 4 (n + 1)$

$(n+1)^3 \ge 4 (n + 1)$

and this is what we were looking for!

So, for any natural equal or greater than 3, the relationship is true.

4 0

3 years ago