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3 years ago

Can I please have some help????

Mathematics

2 answers:

DedPeter [7]3 years ago

8 0

Answer:

avn= -8 + (n-1)(-7)

Step-by-step explanation:

arithmetic sequence formula= avn= av1 + (n-1)d

av1= first number in the sequence

d= common difference

n= the number of the term to find

The common difference is -7 so d=-7 and you plug it into the equation. The first number in the sequence is -8 so av1.

There is no specific n to find so it remains n.

I hope this helps! Let me know if this helps.

Snowcat [4.5K]3 years ago

5 0

Answer:

avn= -8 + (n-1)(-7)

Step-by-step explanation:

arithmetic sequence formula= avn= av1 + (n-1)d

av1= first number in the sequence

d= common difference

n= the number of the term to find

The common difference is -7 so d=-7 and you plug it into the equation. The first number in the sequence is -8 so av1.

There is no specific n to find so it remains n.

I hope this helps! Let me know if this helps.

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√25 + √144 +√100<br>who know pls

pychu [463]

Answer:

Step-by-step explanation:

√ 25 is 5

√ 144 is 12

√ 100 is 10

5 + 12 + 10 = 27

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3 years ago

Solve for x: (1/2) + 4/(2x) = (x + 4)/10

Charra [1.4K]

Answer:

x = 5 , − 4

Step-by-step explanation:

Solve the rational equation by combining expressions and isolating the variable x .

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3 years ago

ANSWER ASAP MUST BE CORRECT

Galina-37 [17]

Solve the second equation for y so that you can substitute it in for y in the first equation..

y = 5x - 4

Substitute:

3x + (5x - 4) = 1

3 0

3 years ago

Read 2 more answers

PLEASE HELP! 13 POINTS! A fitness center has two membership plans. One has a low dollar sign up fee of 15 dollars and costs 38 d

il63 [147K]

Answer:

X = 9 months

Step-by-step explanation:

To solve the number of months when the cost of each payment

are the same, you should equate the two cost. First establish the equations

Let A be the cost of first payment method

B is the cost of the second payment method

X is the number of months

A = 38x + 15

B = 31x + 78

38x + 15 = 31x + 78

7x = 63

X = 9 months

5 0

4 years ago

Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab

Sphinxa [80]

Answer: a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Step-by-step explanation:

Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:

Since we have given that

$\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5$

Using the poisson process, we get that

(a) less than or equal to 12

probability= $P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980$

(b) equal to 13

probability= $P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013$

probability= $P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020$

(d) equal to 20

probability= $P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026$

(e) between 10 and 15, inclusively

probability= $P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318$

Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0

3 years ago