Answer: x=6 y=3 z=2
Step-by-step explanation: The question is very vast so im guessing that its just finding 3 whole numbers that can equal the same ammount being multipied by 2 and 3. I chose 6. But theres many others. The answer should be correct because if we replace the letters with the numbers i put in the answer it should look like this: 6=2•3=3•2
When we do simplify this we should get 6=6=6 which is true.
Again you can use different numbers for example 12 as X. Then you need to divide 12 by whats behind the Y. So 12÷2 is 6. So Y is equal to 6. To find Z all you need to do is follow the same steps as Y. Find the number behind Z (3) and divide that into 12. So it would be 12÷3. And if you do the math right it should look like this: X=12, Y=6, Z= 4. And when you imput the numbers to thier corresponding letter it should look like this 12=2(6)=3(4) which simplified looks like 12=12=12 which is true.
Answer:
hsindvjkdod idbdiid didgejdid idbdusie
Step-by-step explanation:
0gsss hsis % hesjdjzz ud
Answer: Option 'c' is correct.
Step-by-step explanation:
Since we have given that
Number of students who are interested in being on the team = 9
Number of positions to fill on his basket ball team = 3
So, the combinations of the three positions he can choose for the team is given by
Hence, Option 'c' is correct.
Answer:
9
Step-by-step explanation:
A composite number is a number that has factors other than 1 and the number itself.
5 has no factors except 1 and 5. PRIME
2 has no factors except 1 and 2. PRIME
11 has no factors except 1 and 11. PRIME
9 can be multiplied by 3 and 3. COMPOSITE
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hope it helps
Answer:
Add 3 times row 1 to row 2 to obtain the new matrix
Step-by-step explanation:
Attached below is the solution
To obtain the new matrix we will add 3 times Row 1 to row 2
![\left[\begin{array}{ccc}3&-1&-4\\-5&3&8\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-1%26-4%5C%5C-5%263%268%5C%5C%5Cend%7Barray%7D%5Cright%5D)
original matrix
![\left[\begin{array}{ccc}3&-1&-4\\4&0&-4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-1%26-4%5C%5C4%260%26-4%5C%5C%5Cend%7Barray%7D%5Cright%5D)
New Matrix
