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FrozenT [24]
3 years ago
7

Surveys indicate that 5% of the students who took the SATs had enrolled in an SAT prep course. 30% of the SAT prep students were

admitted to their first choice college, as were 20% of the other students. You overhear a classmate say he got into the college he wanted. What is the probability he didn't take an SAT prep course?
What steps would I take to solve this problem?
Mathematics
1 answer:
Nesterboy [21]3 years ago
4 0

Answer: The probability he didn't take an SAT prep course = 0.985

Step-by-step explanation:

Let us first assume that he took SAT prep.

Surveys indicate that 5% of the students who took the SATs had enrolled in an SAT prep course. 30% of the SAT prep students were admitted to their first choice college. That is,

30/ 100 of 5 = 0.3 × 5 = 1.5

The probability he did take an SAT prep course and got admission into the college of first choice will be

P(prep) = 1.5 / 100 = 0.015

The probability he didn't take an SAT prep course will be:

P(not prep) = 1 - P(prep)

P(not prep) = 1 - 0.015

P(not prep) = 0.985

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Two different weight loss programs are being compared to determine their effectiveness. Ten men were assigned to each program (t
True [87]

Answer:

WE reject the Null and conclude that one of the drug is more effective than the other.

Step-by-step explanation:

Given :

Diet 1 3.4 10.9 2.8 7.8 0.9 5.2 2.5 10.5 7.1 7.5

Diet 2 11.9 13.1 11.6 6.8 6.8 8.8 12.5 8.6 17.5 10.3

This is a matched pair sample :

The hypothesis :

H0 : μd = 0

H1 : μd ≠ 0

Hence, we intun the difference between the two groups of value :

Difference, d = -8.9,-2.2,-8.8,1,-5.9,-3.6,-10,1.9,-10.4,-2.8

The test statistic :

dbar ÷ (Sd/√n)

dbar = mean of difference = Σd / n = - 49.7 / 10 = - 4.97

Standard deviation of difference, Sd = 4.51

Test statistic :

-4.97 ÷ (4.51/√10)

Test statistic = - 3.485

The sample size, n = 10

df = n - 1 ; 10 - 1 = 9

Critical value (0.10, 9) = 1.833

If Test statistic > |Critical value |

Since 3.486 > 1.833 ; WE reject the Null and conclude that one of the drug is more effective than the other

5 0
3 years ago
Which of these sequences is a geometric sequence?
podryga [215]
3, 9, 27, 81, 343, 729, … is a geometric sequence because each term is obtained by multiplying 3 to the preceding term.
7 0
3 years ago
Read 2 more answers
Solve the equation on the interval [0,2pi] 5sec(x)+7=-3
vovangra [49]

Answer:

Hello,

x\in \bigg\{\dfrac{2\pi}{3} ,\dfrac{4\pi}{3}\bigg\}\\

Step-by-step explanation:

5*sec(x)+7=-3\\\\sec(x)=\dfrac{-10}{5} \\\\\dfrac{1}{cos(x)} =-2\\\\cos(x)=-\dfrac{1}{2} \\\\x=120^o\ or\ x=240^o\\

8 0
3 years ago
Read 2 more answers
a grocer stacks apples in a pyramid-like stack whose rectangular base is 7 apples by 5 apples. each apple above the first level
g100num [7]

The arrangement of the apples in the stack is in a sequence that can be

used to find the number of apples in each row and in the stack.

Correct response:

  • The number of apples in the stack are <u>85 apples</u>

<h3>How to find the sum of a sequence</h3>

The given parameters are;

Dimensions of apples in the rectangular base = 7 apples by 5 apples

Number of apples on which each apple above rests = 4 apples

Required:

The number of apples in the stack.

Solution:

The dimensions, length and width of the apples in each row decreases

by 1 compared to the row on which the apple rests, as follows;

In the base, the dimension = 7 by 5

In the row directly above, the dimension = (7 - 1) by (5 - 1)

The number of apples sequence continues and is completed by a singles row of apples at the top, from which gives;

Number of apples in the stack = 7 × 5 + 6 × 4 + 5 × 3 + 4 × 2 + 3 × 1 = 85

  • The number of apples in the tack = <u>85 apples</u>

Learn more about sequence and series here:

brainly.com/question/13043887

4 0
2 years ago
The volume of the triangular prism is 12.5 m³. The length is 2.5 m and the base is 2 m. What is the width?
Fantom [35]

Answer:

  (4)  5 m

Step-by-step explanation:

You want the length of side x of a right triangular prism with base edge lengths of 2.5 m and 2 m, and a volume of 12.5 m³.

<h3>Volume</h3>

The volume of the prism is given by the formula ...

  V = Bh

where B is the area of the base:

  B = 1/2bh . . . . where b and h are the leg dimensions of the right triangle

Using these formulas together, we have ...

  V = 1/2(2.5 m)(2 m)x

  12.5 m³ = 2.5x m²

Dividing by 2.5 m², we find x to be ...

  (12.5 m³)/(2.5 m²) = x = 5 m

The dimension labeled x has length 5 meters.

6 0
1 year ago
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