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2 years ago

Help with this please

Mathematics

1 answer:

liubo4ka [24]2 years ago

6 0

Answer:

Step-by-step explanation:

we conformed the 8s by 4 and 3

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Solve the system of equations by graphing on your own paper. Write the

Verdich [7]

Answer:

(9, -1)

Step-by-step explanation:

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3 years ago

You are hiking on a trail that leads to the top of the mountain. At 1 PM you reach an elevation of 4400 feet. At 4 PM you reach

ExtremeBDS [4]

The time from 1 to 4 is 3 hours. (1-2, 2-3, 3-4).

The height you climbed is 1200 feet.

1200/3 is 400.

Your final answer should be 400ft/h

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3 years ago

A 24 foot flagpole casts a 20 foot shadow of the building next to it is an 85 foot shadow find the height of the building

Zigmanuir [339]

Answer: 102 foot / feet tall

Step-by-step explanation:

First, we have to find the unit rate . . . what is 24 divided by 20 ? 1.2/1

Second, multiply . . . what is 1.2 x 85 ? 102

( sorry if this is wrong - I forgot how to do the second part for a sec )

6 0

2 years ago

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

2 years ago

1:0,1+2:0,2+3:0,3...+9:0

s2008m [1.1K]

Answer:

Step-by-step explanation:

answeram I righatjfj

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3 years ago