If two distinct positive divisors of 64 are randomly selected, what is the probability that their sum will be less than 32?
1 answer:
Answer: The required probability is
Step-by-step explanation:
Since we have given that
Divisors of 64= 1,2,4,8,16,32,64
Sum would be less than 32
Since it has 7 divisors in total.
If we select any two distinct divisors from first five divisors, the sum will always less than 32.
So, the probability that their sum will be less than 32 is given by
Hence, the required probability is
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Answer: 1) 5040 and 2) 165
Step-by-step explanation:
1) Here total number of letters = 10
The number of permutations that can be formed using 4 letters at a time
= P (10, 4)
=
=
=
=
= 10 × 9 × 8 × 7
= 5040
2) Here the total number of machine = 11
The different combinations of machines can Geoff choose from to use
=
=
=
=
= 11 × 5 × 3
= 165