If two distinct positive divisors of 64 are randomly selected, what is the probability that their sum will be less than 32?
1 answer:
Answer: The required probability is
Step-by-step explanation:
Since we have given that
Divisors of 64= 1,2,4,8,16,32,64
Sum would be less than 32
Since it has 7 divisors in total.
If we select any two distinct divisors from first five divisors, the sum will always less than 32.
So, the probability that their sum will be less than 32 is given by
Hence, the required probability is
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Answer: B. 84 in²
Step-by-step explanation:
Divide the area into two regions: a rectangle and a trapezoid (depicted in the attached photo).
Find the area of the rectangle:
Area of a rectangle=length*width
Area of rectangle=(5 in)( 10 in)
Area of rectangle=50 in²
Next, calculate the area of the trapezoid:
Area of trapezoid=
h=10 in-6 in
h=4 in
Area of trapezoid=
Area of trapezoid=
Area of trapezoid=
Area of trapezoid=
Add the area of the trapezoid to the area of the rectangle to find the total area: 50 in²+34 in²=84 in²
