By definition, the sine of an angle is given by:
![sin \alpha = \frac{C.O}{h}](https://tex.z-dn.net/?f=sin%20%5Calpha%20%3D%20%20%5Cfrac%7BC.O%7D%7Bh%7D%20)
Where,
C.O: opposite leg
h: hypotenuse
The hypotenuse is given by:
![h = \sqrt{(61}](https://tex.z-dn.net/?f=h%20%3D%20%20%5Csqrt%7B%2861%7D%20)
So, replacing values we have:
![sin \alpha = \frac{5}{\sqrt{61}}](https://tex.z-dn.net/?f=sin%20%5Calpha%20%3D%20%5Cfrac%7B5%7D%7B%5Csqrt%7B61%7D%7D)
Rewriting we have:
Answer:
the sine value of this function is:
A)5 times square root 61 over 61
Answer: Cool!ididnt even no that!
Step-by-step explanation:
Answer:
hi
Step-by-step explanation:
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Answer:
ohhh yea that's a umm carot