find the z scores that seperate the middle 82% of the distribution from the area in the tails of the standard normal distributio
1 answer:
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<h2>Given :-</h2>
- 50 men do 10 hours work daily complete work in 20 days
- 80 men do job in 50% time
- Days required
- 1 man may do job in (50 × 20) days =
- 1 man may do job in 1000 days
Now,
- 80 man = 1000/80 = 12.5
Now,
- When hours reduced 50% then we will multiply days by 2
- Total days = 12.5 × 2 = 25 days.
- Option C is correct