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Juli2301 [7.4K]
2 years ago
14

Suppose the equation 28 = x•4 in the Example is written in the form 4x = 28.

Mathematics
1 answer:
maria [59]2 years ago
6 0

Answer:

Divide each term in

4

x

=

28

by

4

.

4

x

4

=

28

4

Cancel the common factor of

4

.

Tap for more steps...

x

=

28

4

Divide

28

by

4

.

x

=

7

Step-by-step explanation:

hope it helps you

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victus00 [196]

Answer:

the answer will be table -1

Step-by-step explanation:

3 0
3 years ago
A packet of crisps contains 50g. If a “new size” packets contain 15% more, how many grams of crisps are in the “new size” packet
Agata [3.3K]
To solve this, you’d multiply 50 by 1.15 to get 57.5 grams of crisps.
4 0
3 years ago
54 + 81 = 9(6 +_) I need the help to answer my question
Otrada [13]

Answer:

9

Step-by-step explanation:

54+81=9(6+9)

9 times 9 equals 81

7 0
3 years ago
Read 2 more answers
What is the prime factorization of 420?
a_sh-v [17]

we have the factors 2 x 2 x 3 x 5 x 7 = 420. It can also be written in exponential form as 22 x 31 x 51 x 71.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x​
Fofino [41]

Answer:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

Step-by-step explanation:

We are given the function:

f(x)=-4x^5-8x^3+12x

And we want to finds its zeros.

Therefore:

0=-4x^5-8x^3+12x

Firstly, we can divide everything by -4:

0=x^5+2x^3-3x

Factor out an x:

0=x(x^4+2x^2-3)

This is in quadratic form. For simplicity, we can let:

u=x^2

Then by substitution:

0=x(u^2+2u-3)

Factor:

0=x(u+3)(u-1)

Substitute back:

0=x(x^2+3)(x^2-1)

By the Zero Product Property:

x=0\text{ and } x^2+3=0\text{ and } x^2-1=0

Solving for each case:

x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}

Therefore, our real and complex zeros are:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

4 0
3 years ago
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