The correct answer is option B. Genotype AA, phenotype-Unaffected.
The cystic fibrosis is a condition caused by the inheritance of the two recessive allele, It is an autosomal recessive disease.
In the given case, the parents are carriers, and the carriers are always heterozygotes. Hence, the phenotype of the both parent should be Aa. A possible cross of the parents is shown in the figure below.
In case, the progeny have a single dominant trait, the child would not be affected, but will be a carrier and can pass the disease to offspring. In case, the child inherit both the dominant allele (homozygous dominant) from the parents, then he/she would be unaffected. In case, the phenotype of the child is homozygous recessive then it would be affected.
Glycolysis provides a cell with a net gain of 2 ATP molecules
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Answer:
If both parents have sickle cell anemia then the individual will be effected with
sickle cell anemia disease.
Explanation:
It is genetic disease which run in a famalies in an autosomal way.If one parent have sickle cell anemia and other dont then the pregnacy will have 25% of risk and if one Parent have a sickle cell anemia and other have sickle cell trait then the pregnancy will have 50% of chances to be effected.A person having sickle cell trait is that who is not effected with sickle cell anemia and dont have the symptoms of disease but in future if the other parent also have same trait then the pregnancy will be effected.Sickle cell anemia triat is having gene S while normal person have Beta gene.
This disease is common in african desents.