Answer:
In order to get the highest yield, 25 tress should be planted
Step-by-step explanation:
Given the data in the question;
Let n be number bushel, b is bushels per tree, t is number of trees
from the question, if t = 20, b = 30
and if t = 21 then b = 29
so t + b is constant
t + b = 50 ----- let this be equation
now, n = t × b
so b = n / t
hence from equation, we input b = n/t
t + n/t = 50
n/t = 50 - t
n = t(50 - t)
n = 50t - t²
now we get the derivatives
Note, The maximum amount of trees is simply where the derivative is equal zero, so;
0 = 50 - 2t
2t = 50
t = 50/2
t = 25
Therefore, In order to get the highest yield, 25 tress should be planted
