Probabilities are used to determine the chances of events
The given parameters are:
- Sample size: n = 20
- Proportion: p = 85%
<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>
Using the binomial probability formula, we have:

So, the equation becomes
This gives


Express as percentage

Hence, the probability that 11 out of the 20 would graduate is 0.11%
<h3>(b) To what extent do you think the university’s claim is true?</h3>
The probability 0.11% is less than 50%.
Hence, the extent that the university’s claim is true is very low
<h3>(c) What is the probability that all 20 would graduate? </h3>
Using the binomial probability formula, we have:

So, the equation becomes
This gives


Express as percentage

Hence, the probability that all 20 would graduate is 3.88%
<h3>(d) The mean and the standard deviation</h3>
The mean is calculated as:

So, we have:


The standard deviation is calculated as:

So, we have:



Hence, the mean and the standard deviation are 17 and 2.55, respectively.
Read more about probabilities at:
brainly.com/question/15246027