Complete Question
If a logo has dimensions of 6 ft and 11ft, he needs a quart of paint for every 22 square ft. How many quarts will he need for the whole logo?
Answer:
3 quarts of paint
Step-by-step explanation:
The Logo is rectangular in shape, hence:
The area of a rectangle = Length × Width
The logo has dimensions of 6 ft and 11ft.
Area of the Logo = 6ft × 11ft = 66ft²
He needs a quart of paint for every 22 square ft
Hence:
22 ft² = 1 quart of paint
66ft² = x
Cross Multiply
22 ft² × x = 66 ft² × 1 quart
x = 66 ft² × 1 quart/22 ft²
x = 3 quarts of paint
Therefore, he will need 3 quarts of paint for the whole logo.
Answer:
(a) AH < HC is No
(b) AH < AC is Yes
(c) △AHC ≅ △AHB is Yes
Step-by-step explanation:
Given
See attachment for triangle
Solving (a): AH < HC
Line AH divides the triangle into two equal right-angled triangles which are: ABH and ACH (both right-angled at H).
To get the lengths of AH and HC, we need to first determine the measure of angles HAC and ACH. The largest of those angles will determine the longest of AH and HC. Since the measure of the angles are unknown, then we can not say for sure that AH < HC because the possible relationship between both lines are: AH < HC, AH = HC and AH > HC
Hence: AH < HC is No
Solving (b): AH < AC
Length AC represents the hypotenuse of triangle ACH, hence it is the longest length of ACH.
This means that:
AH < AC is Yes
Solving (c): △AHC ≅ △AHB
This has been addresed in (a);
Hence:
△AHC ≅ △AHB is Yes
3 pairs of choices give rise to 2^3 = 8 possibilities:
.. bus, full, morning
.. bus, full, afternoon
.. bus, concession, morning
.. bus, concession, afternoon
.. train, full, morning
.. train, full, afternoon
.. train, concession, morning
.. train, concession, afternoon